I have a simple form with a button to calculate the form. I figure it\'s better to hit the button to start the action of calculating and pass the variables to the dumb function
Shorthand function designed in such a way that it is allowed to return function with type void as mentioned in this article --> So why is returning everything allowed through a shorthand function[()=>] even if the return type is void?
So that you have two approaches in your disposal:
use
onPressed: () => calculate(1, 2),
or
onPressed: (){calculate(1, 2);},
Do you remember the very first line in flutter which is
void main() => runApp(MyApp());
Where =>
represents one line functions or methods
which is key while calling functions with arguments.
Ex:
void display() {
}
we can call the above function by
IconButton(icon: Icon(Icons.add), onPressed: display)
here we can not include ()
with display
But, when there is one or more than one arguments to be passed then it goes like below
void addition(int value1, int value2) {
value1 + value2
}
IconButton(icon: Icon(Icons.add), onPressed: ()=>addition(2, 4))
Use
onPressed: (){calculate(1, 2);},
e.g.
int result = 0;
void calculate(num1, num2) {
setState(() {
result = num1 + num2;
});
}
new RaisedButton(
onPressed: () => calculate(1, 100),
...
),
new Text("$result")
Just found the answer. No. According to the onPressed property of the RaisedButton class, the onPressed property has a type of VoidCallback, which return void and according to the docs VoidCallBack is the Signature of callbacks that have no arguments and return no data.
Edit: Thanks guys. To solve this, you use an anonymous function, like so
(){your code here}