Unix cut except last two tokens

Question

I\'m trying to parse file names in specific directory. Filenames are of format:

token1_token2_token3_token(N-1)_token(N).sh

I need to cut the t

Answer 1

It can not be done with cut, How ever you can use sed or awk

sed -r 's/(_[^_]+){2}$//g'

Answer 2

With cut:

$ echo t1_t2_t3_tn1_tn2.sh | rev | cut -d_ -f3- | rev
t1_t2_t3

rev reverses each line. The 3- in -f3- means from the 3rd field to the end of the line (which is the beginning of the line through the third-to-last field in the unreversed text).

Answer 3

Just a different way to write ysth's answer

echo "t1_t2_t3_tn1_tn2.sh" |rev| cut -d"_" -f1,2 --complement | rev

Answer 4

You may use POSIX defined parameter substitution:

$ name="t1_t2_t3_tn1_tn2.sh"
$ name=${name%_*_*}
$ echo $name
t1_t2_t3