How to make a Django custom management command argument not required?

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梦谈多话
梦谈多话 2021-02-18 19:01

I am trying to write a custom management command in django like below-

class Command(BaseCommand):

    def add_arguments(self, parser):
        parser.add_argum         


        
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  • 2021-02-18 19:40

    You can use the dash syntax for optional keyword arguments:

    class Command(BaseCommand):
    
        def add_arguments(self, parser):
            parser.add_argument("-d", "--delay", type=int)
    
        def handle(self, *args, **options):
            delay = options["delay"] if options["delay"] else 21
            print(delay)
    

    Use:

    $ python manage.py mycommand -d 4
    4
    $ python manage.py mycommand --delay 4
    4
    $ python manage.py mycommand
    21
    

    Docs:

    https://docs.djangoproject.com/en/2.2/howto/custom-management-commands/#s-accepting-optional-arguments

    Simple explanation:

    https://simpleisbetterthancomplex.com/tutorial/2018/08/27/how-to-create-custom-django-management-commands.html#handling-arguments

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  • 2021-02-18 19:51

    One of the recipes from the documentation suggests:

    For positional arguments with nargs equal to ? or *, the default value is used when no command-line argument was present.

    So following should do the trick (it will return value if provided or default value otherwise):

    parser.add_argument('delay', type=int, nargs='?', default=21)
    

    Usage:

    $ ./manage.py mycommand
    21
    $ ./manage.py mycommand 4
    4
    
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