No MediaTypeFormatter is available to read an object of type 'Advertisement' in asp.net web api

前端 未结 3 952
悲哀的现实
悲哀的现实 2021-02-18 18:13

I have a class that name is Advertisement:

 public class Advertisement
{
    public string Title { get; set; }
    public string Desc { get; set; }
}


        
相关标签:
3条回答
  • 2021-02-18 18:18

    "ExceptionMessage": "No MediaTypeFormatter is available to read an object of type 'Advertisement' from content with media type 'application/octet-stream'.",

    That means that your application cannot read octet-stream Content-Type - which is what the request provided. This is one frustration I have with Web API. However there is a way around it. The easy way is to modify the Content-type to 'application/json' or 'application/xml' which is easily read. The harder way is to provide your own MediaTypeFormatter.

    0 讨论(0)
  • 2021-02-18 18:33

    In your WebApiConfig.cs add this inside of register

    config.Formatters.JsonFormatter.SupportedMediaTypes.Add(new MediaTypeHeaderValue("application/octet-stream"));
    
    0 讨论(0)
  • 2021-02-18 18:40

    Several issues:

    1. Instead of posting it as application/octet-stream, use application/json;charset=UTF-8, instead.
    2. public IHttpActionResult Test(Advertisement advertisement) needs to have [FromBody] in it:

      public IHttpActionResult Test([FromBody]Advertisement advertisement) { ... }

      By default, the ApiController expects anything being passed in to represent URL parameters, so you'd need that [FromBody] for any data you are posting in the Request Body that you want parsed out.

    3. You need to decorate your Post method with [System.Web.Http.HttpPost] so that it doesn't think it's the MVC version [System.Web.Mvc.HttpPost]. Ensure you put the full thing, because [HttpPost] will also default to the MVC version. It's probably not a bad idea to rename Test to Post, as well, though you might be using that for a Unit Test method, so not sure on that one.

    4. Send your data as JSON: { Title: "some title", Desc: "some description" }

    5. Do something with advertisement inside your Post() function:

      string title = advertisement.Title; string desc = advertisement.Desc;

    0 讨论(0)
提交回复
热议问题