Python get rid of bytes b' '

Question

import save

string = \"\"

with open(\"image.jpg\", \"rb\") as f:
    byte = f.read(1)
    while byte != b\"\":
        byte = f.read(1)
        print ((byte))
<         


        

Answer 1

The b"..." is just a python notation of byte strings, it's not really there, it only gets printed. Does it cause some real problems to you?

Answer 2

You can use bytes.decode function if you really need to "get rid of b": http://docs.python.org/3.3/library/stdtypes.html#bytes.decode

But it seems from your code that you do not really need to do this, you really need to work with bytes.

Answer 3

The b'', is only the string representation of the data that is written when you print it.

Using decode will not help you here because you only want the bytes, not the characters they represent. Slicing the string representation will help even less because then you are still left with a string of several useless characters ('\', 'x', and so on), not the original bytes.

There is no need to modify the string representation of the data, because the data is still there. Just use it instead of the string (i.e. don't use print). If you want to copy the data, you can simply do:

data = file1.read(...)
...
file2.write(data)

If you want to output the binary data directly from your program, use the sys.stdout.buffer:

import sys

sys.stdout.buffer.write(data)

Answer 4

This is one way to get rid of the b'':

import sys
print(b)

If you want to save the bytes later it's more efficient to read the entire file in one go rather than building a list, like this:

with open('sample.jpg', mode='rb') as fh:
    content = fh.read()
    with open('out.jpg', mode='wb') as out:
        out.write(content)

Answer 5

To operate on binary data you can use the array-module. Below you will find an iterator that operates on 4096 chunks of data instead of reading everything into memory at ounce.

import array

def bytesfromfile(f):
    while True:
        raw = array.array('B')
        raw.fromstring(f.read(4096))
        if not raw:
            break
        yield raw

with open("image.jpg", 'rb') as fd
    for byte in bytesfromfile(fd):
        for b in byte:
            # do something with b 

Answer 6

Here is one solution

print(str(byte[2:-1]))