Whenever I try to open a .csv file with the python command
fread = open(\'input.csv\', \'r\')
it always opens the file with spaces between every single character.
The post by recursive is probably right... the contents of the file are likely encoded with a multi-byte charset. If this is, in fact, the case you can likely read the file in python itself without having to convert it first outside of python.
Try something like:
fread = open('input.csv', 'rb').read()
mytext = fread.decode('utf-16')
The 'b' flag ensures the file is read as binary data. You'll need to know (or guess) the original encoding... in this example, I've used utf-16, but YMMV. This will convert the file to unicode. If you truly have a file with multi-byte chars, I don't recommend converting it to ascii as you may end up losing a lot of the characters in the process.
EDIT: Thanks for uploading the file. There are two bytes at the front of the file which indicates that it does, indeed, use a wide charset. If you're curious, open the file in a hex editor as some have suggested... you'll see something in the text version like 'I.D.|.' (etc). The dot is the extra byte for each char.
The code snippet above seems to work on my machine with that file.
Here's the quick and easy way, esp if python won't parse the input correctly
sed 's/ \(.\)/\1/g'