Using guards in let .. in expressions

Question

Sometimes I write code like this

solveLogic :: Int -> Int -> Int
solveLogic a b =
    let 
        x = 1
        brainiac
            | a >= x     = 1
          


        

Answer 1

When I want guards as an expression I use this somewhat ugly hack

case () of
_ | a >= x     -> 1
  | a == b     -> 333
  | otherwise  -> 5

Answer 2

Yes, using a where clause:

solveLogic a b
        | a >= x     = 1
        | a == b     = 333
        | otherwise  = 5
    where
      x = 1