Libev, How to pass arguments to relevant callbacks

Question

I\'m trapped in a situation of argument passing in libev.

Usually, libev receives packages in a function like *receive_callback*, that\'s OK, but in pra

Answer 1

The author answered it himself, but in a comment. Since this shows up as unanswered, I am posting his answer in the "answer" section and closing the loop. Not sure if there is a better way... feel free to fix this.

Question author says:

Sorry, I think I got the answer now, and feel deeply ashamed at my carelessness of reading documentation:

struct my_io{
   ev_io io;
   int otherfd;
   void *somedata;
   struct whatever *mostinteresting;
};
// ...
struct my_io w;
ev_io_init (&w.io, my_cb, fd, EV_READ);

And then we use the my_io like this:

static void my_cb (struct ev_loop *loop, ev_io *w_, int revents)
{
   struct my_io *w = (struct my_io *)w_;
   //...
}

Answer 2

Yes it's explained in libev document, and there is another way. Each watcher has a void *data member that you can read or modify, and libev will completely ignore it, so you can pass the argument like this:

w->data = (void *)recv_buff;
...
static void my_cb (struct ev_loop *loop, ev_io *w_, int revents)
{
    S_RECV_MSG *recv_buff = (S_RECV_MSG*)w_->data;
    ...
}

see libev document.