Django url pattern regex to pass a email as a parameter in the url

Question

I am writing a view which is accepting a email as parameter passed by url like

url(r\'^admin/detail_consultant_service/((?P\\[A-Z0-9._%+-]+         


        

Answer 1

You are passing a positional argument instead of a keyword argument. The following should work:

{% url consultant_service_detail consultant_id=consultant.id %}

Also if you are using Django>=1.5 you should use the url as follows:

{% url 'consultant_service_detail' consultant_id=consultant.id %}

And since that is a new behavior, you can actually (which is recommended) use in in earlier versions of Django (I think >=1.3) by:

{% load url from future %}
{% url 'view_name' ... %}

The regex I think is fine according to here so the problem is most likely with the definition itself. Try this:

url(r'^admin/detail_consultant_service/(?P<consultant_id>[\w.%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4})/$',
    'admin_tool.views.consultant_service_detail',
    name="consultant_service_detail"),

so a valid url will be similar to:

foo.com/admin/detail_consultant_service/email.address@here.com/

Answer 2

If you have more than one application in a project, which is most likely the case here, your url should be namespaced. The url in the template should be in this format as explained Here

{% url 'My-App-Name:my-url-name' args or kwargs %}

Hence your code shoul look like this,

{% url 'Your-app-Name:consultant_service_detail' consultant_id=consultant.id %}