How to copy folder structure under another directory?

Question

I have some questions related to copying a folder structure. In fact, I need to do a conversion of pdf files to text files. Hence I have such a folder structure for the place wh

Answer 1

How about using shutil.copytree()?

import shutil
def ig_f(dir, files):
    return [f for f in files if os.path.isfile(os.path.join(dir, f))]

shutil.copytree(inputpath, outputpath, ignore=ig_f)

The directory you want to create should not exist before calling this function. You can add a check for that.

Taken from shutil.copytree without files

Answer 2

For me the following works fine:

• Iterate over existing folders

• Build the structure for the new folders based on existing ones

• Check, if the new folder structure does not exist
• If so, create new folder without files

Code:

import os

inputpath = 'D:/f/'
outputpath = 'D:/g/'

for dirpath, dirnames, filenames in os.walk(inputpath):
    structure = os.path.join(outputpath, dirpath[len(inputpath):])
    if not os.path.isdir(structure):
        os.mkdir(structure)
    else:
        print("Folder does already exits!")

Documentation:

• os.walk
• os.mkdir
• os.path.isdir

Answer 3

A minor tweak to your code for skipping pdf files:

for root, dirs, files in os.walk('.', topdown=False):
    for name in files:
        if name.find(".pdf") >=0: continue
        with open("D:/g/"+ ,mode="w") as newfile:
            newfile.write(c.convert_pdf_to_txt(os.path.join(root, name)))