JPQL: The state field path cannot be resolved to a valid type

Question

I can\'t make this query work:

Query query = eManager.createQuery(\"select c FROM News c WHERE c.NEWSID = :id\",News.class);
        return (News)query.setPara         


        

Answer 1

entity have persistent attribute named newsId.but in query you have used NEWSID . try with this

select c FROM News c WHERE c.newsId = :id

Answer 2

That happens because News entity does not have persistent attribute named NEWSID. Names of the persistent attributes are case sensitive in JPQL queries and those should be written with exactly same case as they appear in entity.

Because entity have persistent attribute named newsId, that should also be used in query instead of NEWSID:

select c FROM News c WHERE c.newsId = :id

Answer 3

My entity is:

@Entity
@Table(name = "TBL_PERSON_INFO")
public class Person implements Serializable {
    @Id
    @Column(name = "ID", nullable = false)
    private Integer id;

    @Column(name = "USER_ID", nullable = false)
    private Integer user_id;
    .
    .
    .
}

my query is (JPQL):

String queryName = "from Person p where p.user_id = :user_id";

so I use it like this:

        javax.persistence.Query query = em.createQuery(queryName);
        query.setParameter("user_id", userId);

        try {
            obj = query.getSingleResult();
        }
        catch (javax.persistence.NoResultException nre) {
            logger.error("javax.persistence.NoResultException: " + nre.getMessage());
        }
        catch (javax.persistence.NonUniqueResultException nure) {
            logger.error("javax.persistence.NonUniqueResultException: " + nure.getMessage());
        }
        catch (Exception e) {
            e.printStackTrace();
        }

        if (obj == null) {
            System.out.println("obj is null!");
            return null;
        }

        Person person = (Person) obj;

It's work ;-)