Count all word including numbers in a php string

Question

To count words in a php string usually we can use str_word_count but I think not always a good solution

good example:

$var =\"Hello world!\";
echo str_         


        

Answer 1

I know the question is old, Still i m sharing the fix i have adopt for this.

$str ="Hello world !";
// you can include allowed special characters  as third param.
print_r(str_word_count($str, 1, '!'));

code output is

Array ( [0] => Hello [1] => world [2] => ! )

if you want to include more words u can specify as third param.

print_r(str_word_count($str, 1, '0..9.~!@#$%^&*()-_=+{}[]\|;:?/<>.,'));

from 0..9. will include all numbes, and other special characters are inserted individually.

Answer 2

The following using count() and explode(), will echo:

The number 1 in this line will counted and it contains the following count 8

PHP:

<?php

$text = "The number 1 in this line will counted";

$count = count(explode(" ", $text));

echo "$text and it contains the following count $count";

?>

---

Edit:

Sidenote:
The regex can be modified to accept other characters that are not included in the standard set.

<?php

$text = "The numbers   1  3 spaces and punctuations will not be counted !! . . ";

$text = trim(preg_replace('/[^A-Za-z0-9\-]/', ' ', $text));

$text = preg_replace('/\s+/', ' ', $text);


// used for the function to echo the line of text
$string = $text;

    function clean($string) {

       return preg_replace('/[^A-Za-z0-9\-]/', ' ', $string);

    }

echo clean($string);

echo "<br>";

echo "There are ";
echo $count = count(explode(" ", $text));
echo " words in this line, this includes the number(s).";

echo "<br>";

echo "It will not count punctuations.";

?>