Count all word including numbers in a php string

Question

To count words in a php string usually we can use str_word_count but I think not always a good solution

good example:

$var =\"Hello world!\";
echo str_         


        

Answer 1

You can always split your string by whitespace and count the results:

$res = preg_split('/\s+/', $input);
$count = count($res);

With your string

"The example number 2 is a bad example it will not 
count numbers  and punctuations !!"

This code will produce 16.

The advantage of using this over explode(' ', $string) is that it will work on multi-line strings as well as tabs, not just spaces. The disadvantage is that it's slower.

Answer 2

The most wide-spread method of counting words in a string is by splitting with any kind of whitespace:

count(preg_split('~\s+~u', trim($text)))

Here, '~\s+~u' splits the whole text with any 1 or more Unicode whitespace characters.

The disadvantage is that !! is considered a word.

In case you want to count letter and number words (i.e. strings of text that are only made up of just letters or just numbers) you should consider a preg_match_all like

if (preg_match_all('~[-+]?[0-9]*\.?[0-9]+(?:[eE][-+]?[0-9]+)?|\d+|(?>\p{L}\p{M}*+)+~u', $text, $matches)) {
    return count($matches[0]);
}

See the regex demo and the PHP demo:

$re = '~[-+]?[0-9]*\.?[0-9]+(?:[eE][-+]?[0-9]+)?|\d+|(?>\p{L}\p{M}*+)+~u';
$text = "The example number 2 is a bad example it will not \ncount numbers  and punctuations !! X is 2.5674.";
if (preg_match_all($re, $text, $matches)) {
    echo count($matches[0]);
} // 18 in this string

The [-+]?[0-9]*\.?[0-9]+(?:[eE][-+]?[0-9]+)? regex is a well-known integer or float number regex, and (?>\p{L}\p{M}*+)+ matches any 1 or more letters (\p{L}), each of which can be followed with any amount of diacritic marks (\p{M}*+).

Regex details

• [-+]?[0-9]*\.?[0-9]+(?:[eE][-+]?[0-9]+)? - an optional - or +, 0+ ASCII digits, an optional ., 1+ ASCII digits, an optional sequence of e or E, an optional - or + and then 1+ ASCII digits
• | - or
• \d+ - any 1 or more Unicode digits
• | - or
• (?>\p{L}\p{M}*+)+ - 1 or more occurrences of any Unicode letter followed with any 0+ diacritic symbols.

In case you just want to count text chunks consisting of solely digits and letters (with diacritics) mixed up in any order, you may also use

'~[\p{N}\p{L}\p{M}]+~u'

See another regex demo, \p{M} matches diacritics, \p{N} matches digits and \p{L} matches letters.

Answer 3

You may also use the below code it's working for me.

    function get_num_of_words($string) {
        $string = preg_replace('/\s+/', ' ', trim($string));
        $words = explode(" ", $string);
        return count($words);
    }

    $string="php string word count in simple way";
    echo $count=get_num_of_words($string);

The result will be 7

Answer 4

ans:

function limit_text($text, $limit) {
    if(str_word_count($text, 0) > $limit) {
        $words = str_word_count($text, 2);
        $pos = array_keys($words);
        $text = substr($text, 0, $pos[$limit]) . '...';
    }
    return $text;
}

Answer 5

Use count(explode(' ', $var));

Answer 6

Just some improvement your solution

function stringWordNumberCount($text){
    if (!$text) {
        return 0;
    }

    //Clean the text to remove special character
    $text = trim(preg_replace('/[^A-Za-z0-9\-]/', ' ', $text));

    //Remove continus space on text
    $text = trim( preg_replace('/\s+/', ' ',$text));

    //count space
    return count(explode(' ', $text));

}