Short circuit behavior of logical expressions in C in this example

Question

PROGRAM

#include 

int main(void)
{
    int i, j, k;

    i = 1; j = 1; k = 1;

    printf(\"%d \", ++i || ++j && ++k);
    printf(\"%         


        

Answer 1

Precedence affects only the grouping. && has a higher precedence than || means:

++i || ++j && ++k

is equivalent to:

++i || (++j && ++k)

But that doesn't mean ++j && ++k is evaluated first. It's still evaluated left to right, and according to the short circuit rule of ||, ++i is true, so ++j && ++k is never evaluated.