Calling a lambda expression multiple times

Question

I\'m trying the lambda-expressions from the new standard, and still don\'t understand them quite well.

Let\'s say I have a lambda somewhere in my code, e.g. in my main:<

Answer 1

You can store the lambda using auto, or assign it to a compatible std::function explicitly:

auto f1 = [](int x, int y)->float{ ..... };
std::function<float(int,int)> f2 = [](int x, int y)->float{ ..... };

float x = f1(3,4);
auto y = f2(5,6);

You can always use f1 or f2 to construct or assign to a specific std::function type later on if necessary:

std::function<float(int,int)> f3 = f1;

Answer 2

auto lambda = [](int x, int y)->float
    {
        return static_cast<float>(x) / static_cast<float>(y);
    };
// code
// call lambda
std::cout << lambda(1, 2) << std::endl;