Why false == “false” is false?

Question

I am still learning the basics of javaScript and I don\'t understand why this happens.

Having type coercion false == \"false\"would be converted into:

Answer 1

false == "false" // false

because, the boolean false is converted into 0, so, we compare 0 with "false" and the output is false

Answer 2

These are different kind of items. "string" and boolean.

So:

false.toString() == "false"

Answer 3

You've misunderstood the type conversion rules. false doesn't get converted to a string before comparison.

If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.

false is converted to a number, which gives:

+0 == "false"

… then …

If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).

… "false" is converted to a number, which gives:

+0 == NaN

… which is false.

Answer 4

The answer is because "false" is a string (as Gerardo Furado pointed out in the comments), the test you are making is equivalent to false = "hello".

Javascript does not look at the word in the string to determine if it is a boolean and then try to get the value from that.

Note:

In general in javascript it is now preferred that you use the === operator, to avoid all of this.