I have a table: \"ID name c_counts f_counts \"
and I want to order all the record by sum(c_counts+f_counts)
but this doesn\'t work:
SELECT
Without a GROUP BY clause, any summation will roll all rows up into a single row, so your query will indeed not work. If you grouped by, say, name, and ordered by sum(c_counts+f_counts), then you might get some useful results. But you would have to group by something.
You could try this:
SELECT *
FROM table
ORDER BY (c_counts+f_counts)
LIMIT 20
The problem I see here is that "sum" is an aggregate function.
first, you need to fix the query itself.
Select sum(c_counts + f_counts) total, [column to group sums by]
from table
group by [column to group sums by]
then, you can sort it:
Select *
from (query above) a
order by total
EDIT: But see post by Virat. Perhaps what you want is not the sum of your total fields over a group, but just the sum of those fields for each record. In that case, Virat has the right solution.
Don'y forget that if you are mixing grouped (ie. SUM) fields and non-grouped fields, you need to GROUP BY one of the non-grouped fields.
Try this:
SELECT SUM(something) AS fieldname
FROM tablename
ORDER BY fieldname
OR this:
SELECT Field1, SUM(something) AS Field2
FROM tablename
GROUP BY Field1
ORDER BY Field2
And you can always do a derived query like this:
SELECT
f1, f2
FROM
(
SELECT SUM(x+y) as f1, foo as F2
FROM tablename
GROUP BY f2
) as table1
ORDER BY
f1
Many possibilities!
This is how you do it
SELECT ID,NAME, (C_COUNTS+F_COUNTS) AS SUM_COUNTS
FROM TABLE
ORDER BY SUM_COUNTS LIMIT 20
The SUM function will add up all rows, so the order by
clause is useless, instead you will have to use the group by
clause.