Check if a specific value exists at a specific key in any subarray of a multidimensional array

Question

I need to search a multidimensional array for a specific value in any of the indexed subarrays.

In other words, I need to check a single column of the multidimension

Answer 1

** PHP >= 5.5

simply u can use this

$key = array_search(40489, array_column($userdb, 'uid'));

Let's suppose this multi dimensional array:

$userdb=Array
(
(0) => Array
    (
        (uid) => '100',
        (name) => 'Sandra Shush',
        (url) => 'urlof100'
    ),

(1) => Array
    (
        (uid) => '5465',
        (name) => 'Stefanie Mcmohn',
        (pic_square) => 'urlof100'
    ),

(2) => Array
    (
        (uid) => '40489',
        (name) => 'Michael',
        (pic_square) => 'urlof40489'
    )
);

$key = array_search(40489, array_column($userdb, 'uid'));

Answer 2

If you have to make a lot of "id" lookups and it should be really fast you should use a second array containing all the "ids" as keys:

$lookup_array=array();

foreach($my_array as $arr){
    $lookup_array[$arr['id']]=1;
}

Now you can check for an existing id very fast, for example:

echo (isset($lookup_array[152]))?'yes':'no';

Answer 3

A good solution can be one provided by @Elias Van Ootegan in a comment that is:

$ids = array_column($array, 'id', 'id');
echo isset($ids[40489])?"Exist":"Not Exist";

I tried it and worked for me, thanks buddy.

Edited

Note: It will work in PHP 5.5+

Answer 4

I came upon this post looking to do the same and came up with my own solution I wanted to offer for future visitors of this page (and to see if doing this way presents any problems I had not forseen).

If you want to get a simple true or false output and want to do this with one line of code without a function or a loop you could serialize the array and then use stripos to search for the value:

stripos(serialize($my_array),$needle)

It seems to work for me.

Answer 5

TMTOWTDI. Here are several solutions in order of complexity.

(Short primer on complexity follows):O(n) or "big o" means worst case scenario where n means the number of elements in the array, and o(n) or "little o" means best case scenario. Long discrete math story short, you only really have to worry about the worst case scenario, and make sure it's not n ^ 2 or n!. It's more a measure of change in computing time as n increases than it is overall computing time. Wikipedia has a good article about computational aka time complexity.

If experience has taught me anything, it's that spending too much time optimizing your programs' little-o is a distinct waste of time better spent doing something - anything - better.

Solution 0: O(n) / o(1) complexity:

This solution has a best case scenario of 1 comparison - 1 iteration thru the loop, but only provided the matching value is in position 0 of the array. The worst case scenario is it's not in the array, and thus has to iterate over every element of the array.

foreach ($my_array as $sub_array) {
    if (@$sub_array['id'] === 152) {
        return true;
    }
}
return false;

Solution 1: O(n) / o(n) complexity:

This solution must loop thru the entire array no matter where the matching value is, so it's always going to be n iterations thru the array.

return 0 < count(
    array_filter(
        $my_array,
        function ($a) {
            return array_key_exists('id', $a) && $a['id'] == 152;
        }
    )
);

Solution 2: O(n log n) / o(n log n) complexity:

A hash insertion is where the log n comes from; n hash insertions = n * log n. There's a hash lookup at the end which is another log n but it's not included because that's just how discrete math works.

$existence_hash = [];
foreach ($my_array as $sub_array) {
    $existence_hash[$sub_array['id']] = true;
}
return @$existence_hash['152'];

Answer 6

Try with this below code. It should be working fine for any kind of multidimensional array search.

Here you can see LIVE DEMO EXAMPLE

function multi_array_search($search_for, $search_in) {
    foreach ($search_in as $element) {
        if ( ($element === $search_for) ){
            return true;
        }elseif(is_array($element)){
            $result = multi_array_search($search_for, $element);
            if($result == true)
                return true;
        }
    }
    return false;
}