Why should pop() take an argument?

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不思量自难忘°
不思量自难忘° 2021-02-15 02:25

Quick background
I\'m a Java developer who\'s been playing around with C++ in my free/bored time.

Preface
In C++, you often see

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  • 2021-02-15 02:48

    Using C++0x makes the whole thing hard again.

    As

    stack.pop(item); // move top data to item without copying
    

    makes it possible to efficiently move the top element from the stack. Whereas

    item = stack.top(); // make a copy of the top element
    stack.pop(); // delete top element
    

    doesn't allow such optimizations.

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  • 2021-02-15 02:55

    To answer the question: you should not implement the pop function in C++, since it is already implemented by the STL. The std::stack container adapter provides the method top to get a reference to the top element on the stack, and the method pop to remove the top element. Note that the pop method alone cannot be used to perform both actions, as you asked about.

    Why should it be done that way?

    1. Exception safety: Herb Sutter gives a good explanation of the issue in GotW #82.
    2. Single-responsibility principle: also mentioned in GotW #82. top takes care of one responsibility and pop takes care of the other.
    3. Don't pay for what you don't need: For some code, it may suffice to examine the top element and then pop it, without ever making a (potentially expensive) copy of the element. (This is mentioned in the SGI STL documentation.)

    Any code that wishes to obtain a copy of the element can do this at no additional expense:

    Foo f(s.top());
    s.pop();
    

    Also, this discussion may be interesting.

    If you were going to implement pop to return the value, it doesn't matter much whether you return by value or write it into an out parameter. Most compilers implement RVO, which will optimize the return-by-value method to be just as efficient as the copy-into-out-parameter method. Just keep in mind that either of these will likely be less efficient than examining the object using top() or front(), since in that case there is absolutely no copying done.

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  • 2021-02-15 02:55

    The problem with the Java approach is that its pop() method has at least two effects: removing an element, and returning an element. This violates the single-responsibility principle of software design, which in turn opens door for design complexities and other issues. It also implies a performance penalty.

    In the STL way of things the idea is that sometimes when you pop() you're not interested in the item popped. You just want the effect of removing the top element. If the function returns the element and you ignore it then that's a wasted copy.

    If you provide two overloads, one which takes a reference and another which doesn't then you allow the user to choose whether he (or she) is interested in the returned element or not. The performance of the call will optimal.

    The STL doesn't overload the pop() functions but rather splits these into two functions: back() (or top() in the case of the std::stack adapter) and pop(). The back() function just returns the element, while the pop() function just removes it.

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