How to get first day of every corresponding month in mysql?

Question

I want to get first day of every corresponding month of current year. For example, if user selects \'2010-06-15\', query demands to run from \'2010-06-01\' instead of \'2010

Answer 1

You can use EXTRACT to get the date parts you want:

EXTRACT( YEAR_MONTH FROM DATE('2011-09-28') )
-- 201109

This works well for grouping.

Answer 2

This is old but this might be helpful for new human web crawlers XD

For the first day of the current month you can use:

SELECT LAST_DAY(NOW() - INTERVAL 1 MONTH) + INTERVAL 1 DAY;

Answer 3

SELECT LAST_DAY(date) as last_date, DATE_FORMAT(date,'%Y-%m-01') AS fisrt_date FROM table_name

date=your column name

Answer 4

use date_format method and check just month & year

select * from table_name where date_format(date_column, "%Y-%m")="2010-06"

Answer 5

This works fine for me.

 date(SUBDATE("Added Time", INTERVAL (day("Added Time") -1) day))

** replace "Added Time" with column name

Use Cases:

1. If you want to reset all date fields except Month and Year.

2. If you want to retain the column format as "date". (not as "text" or "number")

Answer 6

You can use the LAST_DAY function provided by MySQL to retrieve the last day of any month, that's easy:

SELECT LAST_DAY('2010-06-15');

Will return:

2010-06-30

Unfortunately, MySQL does not provide any FIRST_DAY function to retrieve the first day of a month (not sure why). But given the last day, you can add a day and subtract a month to get the first day. Thus you can define a custom function:

DELIMITER ;;
CREATE FUNCTION FIRST_DAY(day DATE)
RETURNS DATE DETERMINISTIC
BEGIN
  RETURN ADDDATE(LAST_DAY(SUBDATE(day, INTERVAL 1 MONTH)), 1);
END;;
DELIMITER ;

That way:

SELECT FIRST_DAY('2010-06-15');

Will return:

2010-06-01