Entity Framework - eager loading of related entities

前端 未结 3 908
無奈伤痛
無奈伤痛 2021-02-14 21:44

Sorry the title isn\'t more specific - I didn\'t know how to describe this succinctly. I have Trips and Location that have a many-to-many relationship - straightforward except t

相关标签:
3条回答
  • 2021-02-14 22:08

    Remove the VIRTUAL keyword on your relationship properties e.g.Location, that will disable Lazy Loading and force you to eager load.

    0 讨论(0)
  • 2021-02-14 22:09

    I recreated your scenario here and I was able to get all the results in a single query.

    var a = from trip in context.Trips.Include("TripLocations.Location")
            select trip;
    

    That's all. That's what was queried against my database:

    SELECT 
    [Project1].[TripId] AS [TripId], 
    [Project1].[Name] AS [Name], 
    [Project1].[C1] AS [C1], 
    [Project1].[TripId1] AS [TripId1], 
    [Project1].[LocationId] AS [LocationId], 
    [Project1].[LocationId1] AS [LocationId1], 
    [Project1].[Name1] AS [Name1]
    FROM ( SELECT 
        [Extent1].[TripId] AS [TripId], 
        [Extent1].[Name] AS [Name], 
        [Join1].[TripId] AS [TripId1], 
        [Join1].[LocationId1] AS [LocationId], 
        [Join1].[LocationId2] AS [LocationId1], 
        [Join1].[Name] AS [Name1], 
        CASE WHEN ([Join1].[TripId] IS NULL) THEN CAST(NULL AS int) ELSE 1 END AS [C1]
        FROM  [dbo].[Trips] AS [Extent1]
        LEFT OUTER JOIN  (SELECT [Extent2].[TripId] AS [TripId], [Extent2].[LocationId] AS [LocationId1], [Extent3].[LocationId] AS [LocationId2], [Extent3].[Name] AS [Name]
            FROM  [dbo].[TripLocations] AS [Extent2]
            INNER JOIN [dbo].[Locations] AS [Extent3] ON [Extent2].[LocationId] = [Extent3].[LocationId] ) AS [Join1] ON [Extent1].[TripId] = [Join1].[TripId]
    )  AS [Project1]
    ORDER BY [Project1].[TripId] ASC, [Project1].[C1] ASC
    

    UPDATE:

    If you wanna keep with the lambda version, this will do the work:

    IQueryable<Trip> query = from ride in context.Set<Trip>()
                                 .Include(t=>t.TripLocations.Select(l=>l.Location))                                     
                             select ride;
    

    More information on the MSDN blog.

    0 讨论(0)
  • 2021-02-14 22:22

    Regarding the lambda expression, you can use context.Set like @tyron said or you can use context.Trips. For example:

    IQueryable<Trip> query = from ride in context.Trips
                                 .Include(t=>t.TripLocations.Select(l=>l.Location))                                     
                             select ride;
    

    In order to make this code work, you need to define a property of type DbSet in your DbContext class like below:

    public DbSet<Trip> Trips { get; set; }
    

    Defining a property that returns DbSet is nice but at the same time it's equivalent to accesing context.Set. It's just a code style that could also be combined.

    0 讨论(0)
提交回复
热议问题