POST xml data using java

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独厮守ぢ
独厮守ぢ 2021-02-14 21:04

I have used the following java code to POST xml data to a remote url and get the response. Here, I am using an xml file as the input. What I need is to pass the xml as a string

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  • 2021-02-14 21:50

    The setRequestEntity method on org.apache.commons.httpclient.methods.PostMethod has an overloaded version that accepts StringRequestEntity as argument. You should use this if you wish to pass in your data as a string (as opposed to an input stream). So your code would look something like this:

    String xml = "whatever.your.xml.is.here";
    PostMethod post = new PostMethod(strURL);     
    try {
        StringRequestEntity requestEntity = new StringRequestEntity(xml);
        post.setRequestEntity(requestEntity);
    ....
    

    Hope that helps.

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  • 2021-02-14 21:56

    You can convert the XML to String from this method

    public String convertXMLFileToString(String fileName) 
    { 
       try{ 
           DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance(); 
           InputStream inputStream = new FileInputStream(new File(fileName)); 
           org.w3c.dom.Document doc = documentBuilderFactory.newDocumentBuilder().parse(inputStream); 
           StringWriter stw = new StringWriter(); 
           Transformer serializer = TransformerFactory.newInstance().newTransformer(); 
           serializer.transform(new DOMSource(doc), new StreamResult(stw)); 
           return stw.toString(); 
       } 
       catch (Exception e) { 
           e.printStackTrace(); 
       } 
       return null; 
    }
    

    Add you can pass this string as a parameter on PostMethod like this.

    PostMethod post = new PostMethod(strURL);
    post.addParamter("paramName", convertXMLFileToString(strXMLFilename ) );
    

    The whole XML will be transmitted to the client in a queryString.

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  • 2021-02-14 21:59

    To get your XML file contents as a String use (add catch-block for IOException)

    StringBuilder bld = new StringBuilder();
    FileReader fileReader = new FileReader(input);
    BufferedReader reader = new BufferedReader(fileReader);
    for (String line = reader.readLine(); line != null; line = reader.readLine()) {
        bld.append(line);
    }
    String xml = bld.toString();
    

    The better way is to use Java Web Services JAX-WS or Java Restful Web Services JAX-RS.

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