Proximity sensor in Swift (from Objective-C)

Question

I\'m a relatively new user to swift and now, I need to take advantage of the proximity sensor of an iPhone. I don\'t matter the distance, but I want to know when something is ne

Answer 1

Swift 4

//MARK:- Sensor deduct when hide and show the screen when call
func activateProximitySensor() {
    let device = UIDevice.current
    device.isProximityMonitoringEnabled = true
    if device.isProximityMonitoringEnabled {
        NotificationCenter.default.addObserver(self, selector: #selector(proximityChanged(notification:)), name: NSNotification.Name(rawValue: "UIDeviceProximityStateDidChangeNotification"), object: device)
    }
}

@objc func proximityChanged(notification: NSNotification) {
    if let device = notification.object as? UIDevice {
        print("\(device) detected!")
    }
}

For Removing Observer

 NotificationCenter.default.removeObserver(self, name: .UIDeviceProximityStateDidChange, object: nil)

Answer 2

Swift 3 Version

(Based on Eric Aya's answer)

func setProximitySensorEnabled(_ enabled: Bool) {
    let device = UIDevice.current
    device.isProximityMonitoringEnabled = enabled
    if device.isProximityMonitoringEnabled {
        NotificationCenter.default.addObserver(self, selector: #selector(proximityChanged), name: .UIDeviceProximityStateDidChange, object: device)
    } else {
        NotificationCenter.default.removeObserver(self, name: .UIDeviceProximityStateDidChange, object: nil)
    }
}

func proximityChanged(_ notification: Notification) {
    if let device = notification.object as? UIDevice {
        print("\(device) detected!")
    }
}

Answer 3

Finally I get it working with the answer of Eric D.

Here is the code:

func proximityChanged(notification: NSNotification) {
  if let device = notification.object as? UIDevice {
    println("\(device) detected!")
  }
}
        
func activateProximitySensor() {
  let device = UIDevice.currentDevice()
  device.proximityMonitoringEnabled = true
  if device.proximityMonitoringEnabled {
    NSNotificationCenter.defaultCenter().addObserver(self, selector: "proximityChanged:", name: "UIDeviceProximityStateDidChangeNotification", object: device)
    }
  }
}

and in the viewDidLoad:

override func viewDidLoad() {
  super.viewDidLoad()
  activateProximitySensor()
}

Hope it helps!

Answer 4

Swift 4.2

Activate or deactivate ProximitySensor:

func activateProximitySensor(isOn: Bool) {
    let device = UIDevice.current
    device.isProximityMonitoringEnabled = isOn
    if isOn {
        NotificationCenter.default.addObserver(self, selector: #selector(proximityStateDidChange), name: UIDevice.proximityStateDidChangeNotification, object: device)
    } else {
        NotificationCenter.default.removeObserver(self, name: UIDevice.proximityStateDidChangeNotification, object: device)
    }
}

Selector:

@objc func proximityStateDidChange(notification: NSNotification) {
    if let device = notification.object as? UIDevice {
        print(device)
    }
}

Answer 5

Here's my take on this.

func activateProximitySensor() {
    let device = UIDevice.currentDevice()
    device.proximityMonitoringEnabled = true
    if device.proximityMonitoringEnabled {
        NSNotificationCenter.defaultCenter().addObserver(self, selector: "proximityChanged:", name: "UIDeviceProximityStateDidChangeNotification", object: device)
    }
}

func proximityChanged(notification: NSNotification) {
    if let device = notification.object as? UIDevice {
        println("\(device) detected!")
    }
}