toLowerCase(char) method?

Question

Apparently there is a method that takes a char and returns a char: http://download.oracle.com/javase/6/docs/api/java/lang/Character.html#toLowerCase(char)

But I can\'t s

Answer 1

toLowerCase() is a static method of Character class. So, you will have to use the class name to invoke the method and pass the character which you want to convert to lower case.

Usage--> Character.toLowerCase(<character to be converted to lowercase>)

Other static methods are--> toUpperCase isLowerCase isUpperCase isDigit isAlphabetic

Answer 2

Use your own implementation to convert character to lower case:

c = (char) (c ^ 0x20);

In your method:

public static void main(String[] args) {
        char c = 'A';
        c = (char) (c ^ 0x20);
        System.out.println(c);
       }

Answer 3

toLowerCase is a static method, as such you need to qualify it with the class it belongs to, as

Character.toLowerCase(c);

Answer 4

Try using Character.toLowerCase(c) does that work?

Answer 5

Just add this statement in a header:

import static java.lang.Character.toLowerCase;

Answer 6

"Character" class is used to perform operations on characters of string i.e. to convert character into uppercase, to lower case etc.These methods are "static", So they do not need objects to call them.can be called by class name.

Example: toLowerCase() method of Character class Character.toLowerCase(char ch) converts the character ch argument to lowercase.

Corrected program is as below:

import java.lang.Character;
public class Test {
public static void main(String[] args) {
    char c = 'A';
    c = Character.toLowerCase(c);
    System.out.println(c);
   }
}

Just add the Character before the method toLowerCase() method,because the method is static and should be called by class name.

For more Details Refer following link: http://www.tutorialspoint.com/java/lang/character_tolowercase.htm