I have several questions about new
header in C++ 11. Using Windows 7, Visual Studio 2012.
Looking at the example http://en.cppreference.com/w
1) I'm fairly certain the highest resolution you can get is to use std::chrono::high_resolution_clock
and then don't do any duration casting:
int elapsed_ticks = (end-start).count();
2) Change the argument of duration_cast to something like nanoseconds
:
int elapsed_seconds = std::chrono::duration_cast<std::chrono::nanoseconds>
(end-start).count();
Correct
According to the standard:
system_clock represent[s] wall clock time from the system-wide realtime clock.
The <chrono>
library does not provide a mechanism for measuring CPU time, so if you want that you'll have to fall back on the old <ctime>
library and use std::clock()
.
(And if you're targeting Windows you'll have to fall back on whatever platform-specific API Windows provides for getting CPU time since, as you point out, their std::clock()
doesn't work correctly.)
system_clock
is more like a counterpart to std::time()
than to std::clock()
. (E.g., note that system_clock
provides conversions between system_clock::time_point
s and time_t
.) I imagine that the lack of a clock in <chrono>
for measuring CPU time is due to time constraints on the standard committee and the fact that that functionality is less used than the system's wall clock and real-time clocks.
If you want CPU time but also want the benefits that <chrono>
provides, you should implement a clock type that conforms to the Clock concept outlined in the standard and which provides CPU time, perhaps implemented internally using std::clock()
.
The line that says
int elapsed_seconds = std::chrono::duration_cast<std::chrono::seconds> (end-start).count();
is what causes the time to be rounded to an integral number of seconds. You can choose any period you'd like, or you can use a floating point representation in order to allow non-integral values:
std::int64_t elapsed_attoseconds =
std::chrono::duration_cast<std::chrono::duration<std::int64_t, std::atto>>
(end-start).count();
double elapsed_seconds =
std::chrono::duration_cast<std::chrono::duration<double,std::ratio<1>>>
(end-start).count();
Note that in real code you should avoid using .count()
to escape the strong typing provided by chrono::duration
until you absolutely must.
auto total_duration = end - start;
auto seconds = std::chrono::duration_cast<std::chrono::seconds>(total_duration);
auto milli = std::chrono::duration_cast<std::chrono::milliseconds>(total_duration - seconds);
std::cout << seconds.count() << "s " << milli.count() << "ms\n";