How to Yield in a recursive function in Python

Question

So I have a dictionary:

{\'a\': {\'b\': {\'c\': \'d\', \'e\': \'f\'}}}

I need to create a dictionary as follows:

{\'c\':\'d\',          


        

Answer 1

You are ignoring the generator object that the recursive call produces:

for key, item in data.items():
    boil_down_array(key, item)  # creates a generator object

so the recursive call is not actually executed (the code in your generator is never executed for that call).

You want to use yield from to delegate iteration to that call:

for key, item in data.items():
    yield from boil_down_array(key, item)

yield from moves control from the current generator to the iterator that the expression after yield from produces; here that's your recursive generator.

yield from requires Python 3.3 or newer. If you are using Python 2 or an older Python 3 release, you can also add another loop to explicitly yield each result produced by iteration:

for key, item in data.items():
    for result in boil_down_array(key, item):
        yield result

I'd also use isinstance(data, dict) rather than use type(...) ==, to allow for subclasses:

def boil_down_array(key, data):
    if isinstance(data, dict):
        for key, item in data.items():
            yield from boil_down_array(key, item)
    else:
        yield {key: data}

Note that your code doesn't actually produce a dictionary as output. It produces an iterable of single key-value dictionaries:

>>> d = {'a': {'b': {'c': 'd', 'e': 'f'}}}
>>> list(boil_down_array('v', d))
[{'c': 'd'}, {'e': 'f'}]

The key argument from the outermost call is redundant here too, as you replace it with the key of the current iteration.

If you do need to stick with a generator function, then at least produce (key, value) tuples and don't bother with recursing when the value is not a dictionary (so test before you recurse), to remove the need to pass along the key; the remaining data argument is now assumed to be a dictionary, always:

def boil_down_nested(data):
    for key, value in data.items():
        if isinstance(value, dict):
            yield from boil_down_nested(value)
        else:
            yield (key, value)

and use dict(boil_down_nested(input_dict)) to produce a new dictionary from the key-value tuples the generator now outputs:

>>> next(boil_down_nested(d))  # first resulting key-value pair
('c', 'd')
>>> dict(boil_down_nested(d))  # all key-value pairs into a dictionary.
{'c': 'd', 'e': 'f'}

Without recursion, you can use a stack to track nested dictionaries still to process; this makes it much easier to just output a dictionary as a result directly:

def boil_down_nested_dict(d):
    stack = [d]
    output = {}
    while stack:
        for key, value in stack.pop().items():
            if isinstance(value, dict):
                stack.append(value)  # process this value next
            else:
                output[key] = value
    return output

No separate dict() call required anymore:

>>> boil_down_nested_dict(d)
{'c': 'd', 'e': 'f'}

Answer 2

Note that you do not necessarily need to use yield:

def last(d):
  c = [i for b in d.items() for i in ([b] if not isinstance(b[-1], dict) else last(b[-1]))]
  return c

print(dict(last({'a': {'b': {'c': 'd', 'e': 'f'}}})))

Output:

{'c': 'd', 'e': 'f'}

Answer 3

Use yield from with your recursive call, otherwise you are just ignoring the result of the recursive call:

def boil_down_array(key, data):
    if type(data) == dict:
        for key, item in data.items():
            yield from boil_down_array(key, item)
    else:
        yield {key: data}

This is only available in Python > 3.3, but essentially just a short hand for simply yielding from an extra loop:

for key, item in data.items():
    for x in boil_down_array(key, item):  # just exhaust the recursive generator
        yield x  # and "re-yield" what it produces

In order to achieve your desired data structure, you might be better off yielding pairs instead of dicts, so you can transform the result more easily to the resulting dict:

yield key, data

Then you can use it like:

result = dict(boil_down_array(None, input_dict))

An even simpler recursive approach will just return a complete dict:

def boil_down_nested(dct):
    result = {}
    for k, v in dct.items():
        if isinstance(v, dict):
            result.update(boil_down_nested(v))
        else:
            result[k] = v
    return result