subprocess.call logger info and error for stdout and stderr respectively

Question

I have a logger. something like this:

import logging

logger = logging.getLogger(\'myApp\')
hdlr = logging.FileHandler(\'myApp.log\')
logger.addHandler(hdlr)
log         


        

Answer 1

Use subprocess.Popen() and call .communicate() on the returned process object:

p = subprocess.Popen(["someCommand"], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout, stderr = p.communicate()

if stdout:
    logger.info(stdout)
if stderr:
    logger.error(stderr)