I have an array and would like to sort all but the last n elements.
For example, if the array is 10 elements long, would like elements 0 through 7 to be sorted while ele
An ES6 riff on the solution provided by @darin
let subSort = (arr, i, n, sortFx) => [].concat(...arr.slice(0, i), ...arr.slice(i, i + n).sort(sortFx), ...arr.slice(i + n, arr.length));
So it's possible to sort a range within an array:
var array = [5, 2, 6, 4, 1, 9, 3, 8, 7];
// sort array beginning at index 2; sort 4 elements of array
subSort(array, 2, 4, (a, b) => a - b);
// array is now [5, 2, 1, 4, 6, 9, 3, 8, 7]
subSort(array, 2, 4, (a, b) => b - a);
// array is now [5, 2, 9, 6, 4, 1, 3, 8, 7]
subSort() can be used for objects of arbitrary complexity.
var array = [5, 2, 6, 4, 1, 9, 3, 8, 7];
array = array.slice(0, 7).sort().concat(array.slice(7, 10));
// array is now [1, 2, 3, 4, 5, 6, 9, 8, 7]
If you need to sort the array in place (i.e. without creating a new, sorted array), which is what the sort()
method does, you could do the following:
var array = [5, 2, 6, 4, 0, 1, 9, 3, 8, 7];
var unsorted = array.slice(7);
array.length = 7;
array.sort().push.apply(array, unsorted);
More generally, here's a function to sort a portion of an array in place. Like the sort()
method, it also returns a reference to the array.
function partialSort(arr, start, end) {
var preSorted = arr.slice(0, start), postSorted = arr.slice(end);
var sorted = arr.slice(start, end).sort();
arr.length = 0;
arr.push.apply(arr, preSorted.concat(sorted).concat(postSorted));
return arr;
}
Example:
var array = [5, 2, 6, 4, 0, 1, 9, 3, 8, 7];
partialSort(array, 0, 7);