I have an expression as: 1/(x+1)+4*x/(x-1)+3-4*x**2+10*x**2
What I need is a list that contain the terms in this expression.
i.e. [1/(x+1), 4*x/(x
Based on the question and comments, if you can get the expression as a string, you can do something like this if you want to avoid term collection.
(sympify("1/(x+1)+4*x/(x-1)+3-4*x**2+10*x**2", evaluate=False)).args
this will return all the terms without collecting like terms.
In this case it is very easy:
>>> expr = 1/(x+1)+4*x/(x-1)+3-4*x**2
>>> expr.args
⎛ 1 2 4⋅x ⎞
⎜3, ─────, -4⋅x , ─────⎟
⎝ x + 1 x - 1⎠
The right way to do this is Add.make_args
. This is the same things as expr.args
from Bjoern's answer, except if the expression is not an Add
(a single term), it still gives that term, instead of traversing into that expression.
In [20]: expr = 1/(x+1)+4*x/(x-1)+3-4*x**2
In [21]: print(Add.make_args(expr))
(3, 1/(x + 1), -4*x**2, 4*x/(x - 1))