How can I use getimagesize() with $_FILES['']?

Question

I am doing an image upload handler and I would like it to detect the dimensions of the image that\'s been uploaded by the user.

So I start with:

if (isse         


        

Answer 1

from php manual very simple example.

list($width, $height, $type, $attr) = getimagesize("img/flag.jpg");
echo "<img src=\"img/flag.jpg\" $attr alt=\"getimagesize() example\" />";

Answer 2

You can do this as such

$filename = $_FILES['image']['tmp_name'];
$size = getimagesize($filename);

// or

list($width, $height) = getimagesize($filename);
// USAGE:  echo $width; echo $height;

Using the condition combined, here is an example

if (isset($_FILES['image'])) {
    $filename = $_FILES['image']['tmp_name'];
    list($width, $height) = getimagesize($filename);
    echo $width; 
    echo $height;    
}

Answer 3

list($w, $h) = getimagesize($_FILES['image']['tmp_name']);

From the docs:

Index 0 and 1 contains respectively the width and the height of the image.

Index 2 is one of the IMAGETYPE_XXX constants indicating the type of the image.

Index 3 is a text string with the correct height="yyy" width="xxx" string that can be used directly in an IMG tag.

So you can just do list() and don't worry about indexes, it should get the info you need :)

Answer 4

Try this for multi images :

for($i=0; $i < count($filenames); $i++){  

    $image_info = getimagesize($images['tmp_name'][$i]);
    $image_width  = $image_info[0];
    $image_height = $image_info[1];
}

Try this for single image :

$image_info = getimagesize($images['tmp_name']);
$image_width  = $image_info[0];
$image_height = $image_info[1];

at least it works for me.