Switching back and forth between Array of Structures (AoS) and Structure of Arrays (SoA)

Question

One feature that plays a prominent role in many of the writings on data oriented design is that there are many cases where rather than AoS (array of structs):

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Answer 1

I'm going to choose this syntax: cs.foo[42] to be the single syntax and use typedefs to switch between arrangements:

So, obviously given C_SoA from your post, the above syntax works and we can have:

typedef C_SoA Arrangement;

Arrangement cs;

In order to use std::vector<C_AoS> instead we are going to have to introduce something else:

typedef std::vector<C_AoS> AOS;

template<class A, class C, class T>
struct Accessor {
    T operator[](size_t index){
            return arr[index].*pMember;
    }
    T (C::*pMember);
    A& arr;
    Accessor(A& a, T (C::*p)): arr(a), pMember(p){}
};

struct Alt_C_AoS{
    Accessor<AOS, C_AoS, int> foo;
    Accessor<AOS, C_AoS, double> bar;

    AOS aos;
    Alt_C_AoS():foo(aos, &C_AoS::foo), bar(aos, &C_AoS::bar){}
};

Now we can have:

//Choose just one arrangement
typedef Alt_C_AoS Arrangement;
//typedef C_SoA Arrangement;

Arrangement cs;
...
std::cout << cs.foo[42] << std::endl;

Essentially this converts container dot member index into container index dot member.