How to submit a specific form if multiple forms are present in one page using jquery

Question

I have two forms.

Answer 1

you would say

<input type="submit" name="btn1" id="btn1" value="Submit"/>

 $("#btn1").click(function(){  
  $("#frm1").submit();
}

and

<input type="submit" name="btn2" id="btn2" value="Submit"/>

 $("#btn2").click(function(){  
  $("#frm1").submit();
}

Answer 2

I usually avoid the .submit() function as i almost always have to do something more with response that .submit() would allow me to do.

Thus, a non .submit option where you SUBMIT buttons would have to be changed to normal buttons.

$('.btn2').bind('click', function(){

    var form1Data = $('#frm1').serialize();
    $.ajax({
        url : 'someurl',
        type : 'post',
        datatype : 'json',
        data : form1Data,
        success : function(json) {
            sumbitForm2();
        }
    });
});

function submitForm2() {

    var form2Data = $('#frm2').serialize(); 
    $.ajax({
        url : 'urlToSumbitForm1',
        type : 'post',
        datatype : 'json',
        data : form2Data,
        success : function(json) {
            //do something if you need to
        }
    });
}

Answer 3

<button type="submit" form="form1" value="Submit">Submit</button>

The form attribute specifies the id of the form that the button will submit.

Answer 4

HTML

<form name="frm1" action="someurl" method="post" id="frm1">
<input type="submit" name="btn1" class="buttons" value="Submit"/>
</form>


<input type="submit" name="btn2" onclick="formSubmit()" value="Submit"/>

Javascript

<script>
function formSubmit()
{
document.getElementById("frm1").submit();
}
</script>

Answer 5

consider the HTML:

    <form id="target" action="destination.html">
    <input type="text" value="Hello there" />
    <input type="submit" value="Go" />
    </form>
    <div id="other">
    ....
    </div>

The event handler can be bound to the form:

    $('#target').submit(function() {
    alert('Handler for .submit() called.');
    return false;
    });

Click function:

    $('#other').click(function() {
    $('#target').submit();
    });

Here is the link have a look: How can I submit form on button click when using preventDefault()?

Answer 6

You can use ajax to submit the first form before the second one:

$('form[name=frm2]').submit(function() {
    var form1 = $('form[name=frm1]');
    $.ajax({
        type: "POST",
        url: form1.attr('action'),
        data: form1.serialize(),
        async: false;
    });
});