decimal in c# misunderstanding?

Question

(while trying to analyze how decimal works ) && after reading @jonskeet article and seeing msdn , and thinking for the last 4 hours , I have some

Answer 1

They've given the range to just two significant digits, but specified the precision separately. That's why the range is listed as "approximate range".

The decimal representation of 0.5 would be a mantissa of 5 and an exponent of 1 (which is treated in the inverse sense to normal, i.e. it's effectively -1).

Answer 2

why do they write 28-29 but display 2?

For readability. It says "Approximate range" and 7.9E28 is more readable than 79228162514264337593543950335 (E0 here, not E1).

how will decimal representation ( mantiss && exponent) will be displayed for the value 0.5 ?

The exponent's range is -28...0, however, it is stored (and received via constructor parameters) as an absolute value of 0...28.

So 0.5 Would have the same mantissa representation as 5 with an exponent of -1 (stored as 1).