Get integer value from string in swift

Question

So I can do this:

var stringNumb: NSString = \"1357\"

var someNumb: CInt = stringNumb.intValue

But I can\'t find the way to do it w/ a

Answer 1

Convert String to Int in Swift 2.0:

var str:NSString = Data as! NSString
var cont:Int = str.integerValue

use .intergerValue or intValue for Int32

Answer 2

The method you want is toInt() -- you have to be a little careful, since the toInt() returns an optional Int.

let stringNumber = "1234"
let numberFromString = stringNumber.toInt()
// numberFromString is of type Int? with value 1234

let notANumber = "Uh oh"
let wontBeANumber = notANumber.toInt()
// wontBeANumber is of type Int? with value nil

Answer 3

above answer didnt help me as my string value was "700.00"

with Swift 2.2 this works for me

let myString = "700.00"
let myInt = (myString as NSString).integerValue

I passed myInt to NSFormatterClass

let formatter = NSNumberFormatter()
formatter.numberStyle = .CurrencyStyle
formatter.maximumFractionDigits = 0

let priceValue = formatter.stringFromNumber(myInt!)!

//Now priceValue is ₹ 700

Thanks to this blog post.

Answer 4

You can bridge from String to NSString and convert from CInt to Int like this:

var myint: Int = Int(stringNumb.bridgeToObjectiveC().intValue)

Answer 5

I'd use:

var stringNumber = "1234"
var numberFromString = stringNumber.toInt()
println(numberFromString)

Note toInt():

If the string represents an integer that fits into an Int, returns the corresponding integer.

Answer 6

I wrote an extension for that purpose. It always returns an Int. If the string does not fit into an Int, 0 is returned.

extension String {
    func toTypeSafeInt() -> Int {
        if let safeInt = self.toInt() {
            return safeInt
        } else {
            return 0
        }
    }
}