Store multidimensional array in database: relational or multidimensional?

Question

I have read numerous posts along the lines of multidimensional to single dimension, multidimensional database, and so on, but none of the answers helped. I did

Answer 1

I have two words for you... "RANGE KEYS"

You may find this technique to be incredibly powerful and flexible. You'll be able to navigate your hierarchies with ease, and support variable depth aggregation without the need for recursion.

In the demonstration below, we'll build the hierarchy via a recursive CTE. For larger hierarchies 150K+, I'm willing to share a much faster build in needed.

Since your hierarchies are slow moving (like mine), I tend to store them in a normalized structure and rebuild as necessary.

How about some actual code?

Declare @YourTable table (ID varchar(25),Pt varchar(25))
Insert into @YourTable values 
('A'   ,NULL),
('AA'  ,'A'),
('AAA' ,'AA'),
('AAC' ,'AA'),
('AB'  ,'A'),
('AE'  ,'A'),
('AEA' ,'AE'),
('AEE' ,'AE'),
('AEEB','AEE')


Declare @Top  varchar(25) = null     --<<  Sets top of Hier Try 'AEE'
Declare @Nest varchar(25) ='|-----'  --<<  Optional: Added for readability

IF OBJECT_ID('TestHier') IS NOT NULL 
Begin
    Drop Table TestHier
End

;with cteHB as (
      Select Seq  = cast(1000+Row_Number() over (Order by ID) as varchar(500))
            ,ID
            ,Pt
            ,Lvl=1
            ,Title = ID
      From   @YourTable 
      Where  IsNull(@Top,'TOP') = case when @Top is null then isnull(Pt,'TOP') else ID end
      Union  All
      Select cast(concat(cteHB.Seq,'.',1000+Row_Number() over (Order by cteCD.ID)) as varchar(500))
            ,cteCD.ID
            ,cteCD.Pt
            ,cteHB.Lvl+1
            ,cteCD.ID
      From   @YourTable cteCD 
      Join   cteHB on cteCD.Pt = cteHB.ID)
     ,cteR1 as (Select Seq,ID,R1=Row_Number() over (Order By Seq) From cteHB)
     ,cteR2 as (Select A.Seq,A.ID,R2=Max(B.R1) From cteR1 A Join cteR1 B on (B.Seq like A.Seq+'%') Group By A.Seq,A.ID )
Select B.R1  
      ,C.R2
      ,A.ID
      ,A.Pt
      ,A.Lvl
      ,Title = Replicate(@Nest,A.Lvl-1) + A.Title
 Into dbo.TestHier
 From cteHB A
 Join cteR1 B on A.ID=B.ID
 Join cteR2 C on A.ID=C.ID
 Order By B.R1

---

Show The Entire Hier I added the Title and Nesting for readability

Select * from TestHier Order By R1

Just to state the obvious, the Range Keys are R1 and R2. You may also notice that R1 maintains the presentation sequence. Leaf nodes are where R1=R2 and Parents or rollups define the span of ownership.

---

To Show All Descendants

Declare @GetChildrenOf varchar(25) = 'AE'
Select A.*
  From TestHier A
  Join TestHier B on B.ID=@GetChildrenOf and A.R1 Between B.R1 and B.R2
  Order By R1

---

To Show Path

Declare @GetParentsOf varchar(25) = 'AEEB'
Select A.*
  From TestHier A
  Join TestHier B on B.ID=@GetParentsOf and B.R1 Between A.R1 and A.R2
  Order By R1

Clearly these are rather simple illustrations. Over time, I have created a series of helper functions, both Scalar and Table Value Functions. I should also state that you should NEVER hard code range key in your work because they will change.

In Summary

If you have a point (or even a series of points), you'll have its range and therefore you'll immediately know where it resides and what rolls into it.

Answer 2

You absolutely can do that (if I've read your question correctly).

Depending on your RDBMS you might have to choose a different way.

Your basic structure of having a parent is correct.

SQL Server use recursive common table expression (CTE) to anchor the start and work down

https://technet.microsoft.com/en-us/library/ms186243(v=sql.105).aspx

Edit: For Linux use the same in PostgreSQL https://www.postgresql.org/docs/current/static/queries-with.html

Oracle has a different approach, though I think you might be able to use the CTE as well.

https://oracle-base.com/articles/misc/hierarchical-queries

For 100k rows I don't imagine performance will be an issue, though I'd still index PK & FK because that's the right thing to do. If you're really concerned about speed then reading it into memory and building a hash table of linked lists might work.

Pros & cons - it pretty much comes down to readability and suitability for your RDBMS.

It's an already solved problem (again, assuming I've not missed anything) so you'll be fine.

Answer 3

For your scenario, I would suggest you to use Nested Sets Approach in PostgreSQL. It is XML tags based querying using Relational database.

Performance

If you index on lft and rgt columns, then you don't require recursive queries to get the data. Even though, the data seems huge, the retrieval will be very fast.

Sample

/*1A:
2  AA:
3    AAA
4    AAC
5  AB
6  AE:
7   AEA
8   AEE:
9     AEEB
10B:
*/

CREATE TABLE tree(id int, CELL varchar(4), lft int, rgt int);
    
INSERT INTO tree
    ("id", CELL, "lft", "rgt")
VALUES
    (1, 'A', 1, 9),
    (2, 'AA', 2, 4),
    (3, 'AAA', 3, 3),
    (4, 'AAC', 4, 4),
    (5, 'AB', 5, 5),
    (6, 'AE', 6, 9),
    (7, 'AEA', 7, 7),
    (8, 'AEE', 8, 8),
    (9, 'AEEB', 9, 9)
;


SELECT  hc.*
FROM    tree hp
JOIN    tree hc
ON      hc.lft BETWEEN hp.lft AND hp.rgt
WHERE   hp.id = 2

Demo

Querying using Nested Sets approach

Answer 4

The goal is to retrieve an element with PHP by name and all its descendants.

If that is all you need, you can use a LIKE search

SELECT *
FROM Table1
WHERE CELL LIKE 'AEE%';

With an index beginning with CELL this is a range check, which is fast.

If your data doesn't look like that, you can create a path column which looks like a directory path and contains all nodes "on the way/path" from root to the element.

| id | CELL | parent_id | path     |
|====|======|===========|==========|
|  1 | A    |      NULL | 1/       |
|  2 | AA   |         1 | 1/2/     |
|  3 | AAA  |         2 | 1/2/3/   |
|  4 | AAC  |         2 | 1/2/4/   |
|  5 | AB   |         1 | 1/5/     |
|  6 | AE   |         1 | 1/6/     | 
|  7 | AEA  |         6 | 1/6/7/   |
|  8 | AEE  |         6 | 1/6/8/   |
|  9 | AEEB |         8 | 1/6/8/9/ |

To retrieve all descendants of 'AE' (including itself) your query would be

SELECT *
FROM tree t
WHERE path LIKE '1/6/%';

or (MySQL specific concatenation)

SELECT t.*
FROM tree t
CROSS JOIN tree r -- root
WHERE r.CELL = 'AE'
  AND t.path LIKE CONCAT(r.path, '%');

Result:

| id | CELL | parent_id |     path |
|====|======|===========|==========|
|  6 | AE   |         1 | 1/6/     |
|  7 | AEA  |         6 | 1/6/7/   |
|  8 | AEE  |         6 | 1/6/8/   |
|  9 | AEEB |         8 | 1/6/8/9/ |

Demo

Performance

I have created 100K rows of fake data on MariaDB with the sequence plugin using the following script:

drop table if exists tree;
CREATE TABLE tree (
  `id` int primary key,
  `CELL` varchar(50),
  `parent_id` int,
  `path` varchar(255),
  unique index (`CELL`),
  unique index (`path`)
);

DROP TRIGGER IF EXISTS `tree_after_insert`;
DELIMITER //
CREATE TRIGGER `tree_after_insert` BEFORE INSERT ON `tree` FOR EACH ROW BEGIN
    if new.id = 1 then
        set new.path := '1/';
    else    
        set new.path := concat((
            select path from tree where id = new.parent_id
        ), new.id, '/');
    end if;
END//
DELIMITER ;

insert into tree
    select seq as id
        , conv(seq, 10, 36) as CELL
        , case 
            when seq = 1 then null
            else floor(rand(1) * (seq-1)) + 1 
        end as parent_id
        , null as path
    from seq_1_to_100000
;
DROP TRIGGER IF EXISTS `tree_after_insert`;
-- runtime ~ 4 sec.

Tests

Count all elements under the root:

SELECT count(*)
FROM tree t
CROSS JOIN tree r -- root
WHERE r.CELL = '1'
  AND t.path LIKE CONCAT(r.path, '%');
-- result: 100000
-- runtime: ~ 30 ms

Get subtree elements under a specific node:

SELECT t.*
FROM tree t
CROSS JOIN tree r -- root
WHERE r.CELL = '3B0'
  AND t.path LIKE CONCAT(r.path, '%');
-- runtime: ~ 30 ms

Result:

| id    | CELL | parent_id | path                                |
|=======|======|===========|=====================================|
|  4284 | 3B0  |       614 | 1/4/11/14/614/4284/                 |
|  6560 | 528  |      4284 | 1/4/11/14/614/4284/6560/            |
|  8054 | 67Q  |      6560 | 1/4/11/14/614/4284/6560/8054/       |
| 14358 | B2U  |      6560 | 1/4/11/14/614/4284/6560/14358/      |
| 51911 | 141Z |      4284 | 1/4/11/14/614/4284/51911/           |
| 55695 | 16Z3 |      4284 | 1/4/11/14/614/4284/55695/           |
| 80172 | 1PV0 |      8054 | 1/4/11/14/614/4284/6560/8054/80172/ |
| 87101 | 1V7H |     51911 | 1/4/11/14/614/4284/51911/87101/     |

PostgreSQL

This also works for PostgreSQL. Only the string concatenation syntax has to be changed:

SELECT t.*
FROM tree t
CROSS JOIN tree r -- root
WHERE r.CELL = 'AE'
  AND t.path LIKE r.path || '%';

Demo: sqlfiddle - rextester

How does the search work

If you look at the test example, you'll see that all paths in the result begin with '1/4/11/14/614/4284/'. That is the path of the subtree root with CELL='3B0'. If the path column is indexed, the engine will find them all efficiently, because the index is sorted by path. It's like you would want to find all the words that begin with 'pol' in a dictionary with 100K words. You wouldn't need to read the entire dictionary.

Answer 5

This approach does not depend on the existence of a path or parent column. It is relational not recursive.

Since the table is static create a materialized view containing just the leaves to make searching faster:

create materialized view leave as
select cell
from (
    select cell,
        lag(cell,1,cell) over (order by cell desc) not like cell || '%' as leave
    from t
) s
where leave;

table leave;
 cell 
------
 CCCE
 CCCA
 CCBE
 CCBC
 BEDA
 BDDA
 BDCE
 BDCB
 BAA
 AEEB
 AEA
 AB
 AAC
 AAA

A materialized view is computed once at creation not at each query like a plain view. Create an index to speed it up:

create index cell_index on leave(cell);

If eventually the source table is altered just refresh the view:

refresh materialized view leave;

The search function receives text and returns a text array:

create or replace function get_descendants(c text)
returns text[] as $$
    select array_agg(distinct l order by l)
    from (
        select left(cell, generate_series(length(c), length(cell))) as l
        from leave
        where cell like c || '%'
    ) s;
$$ language sql immutable strict;

Pass the desired match to the function:

select get_descendants('A');
          get_descendants          
-----------------------------------
 {A,AA,AAA,AAC,AB,AE,AEA,AEE,AEEB}

select get_descendants('AEE');
 get_descendants 
-----------------
 {AEE,AEEB}

Test data:

create table t (cell text);
insert into t (cell) values
('A'),
('AA'),
('AAA'),
('AAC'),
('AB'),
('AE'),
('AEA'),
('AEE'),
('AEEB'),
('B'),
('BA'),
('BAA'),
('BD'),
('BDC'),
('BDCB'),
('BDCE'),
('BDD'),
('BDDA'),
('BE'),
('BED'),
('BEDA'),
('C'),
('CC'),
('CCB'),
('CCBC'),
('CCBE'),
('CCC'),
('CCCA'),
('CCCE'),
('CE');

Answer 6

Performance

As others have already mentioned, performance shouldn't be an issue as long as you use a suitable indexed primary key and ensure that relations use foreign keys. In general, an RDBMS is highly optimised to efficiently perform joins on indexed columns and referential integrity can also provide the advantage of preventing orphans. 100,000 may sound a lot of rows but this isn't going to stretch an RDBMS as long as the table structure and queries are well designed.

Choice of RDBMS

One factor in answering this question lies in choosing a database with the ability to perform a recursive query via a Common Table Expression (CTE), which can be very useful to keep the queries compact or essential if there are queries that do not limit the number of descendants being traversed.

Since you've indicated that you are free to choose the RDBMS but it must run under Linux, I'm going to throw PostgreSQL out there as a suggestion since it has this feature and is freely available. (This choice is of course very subjective and there are advantages and disadvantages of each but a few other contenders I'd be tempted to rule out are MySQL since it doesn't currently support CTEs, MariaDB since it doesn't currently support *recursive* CTEs, SQL Server since it doesn't currently support Linux. Other possibilities such as Oracle may be dependent on budget / existing resources.)

SQL

Here's an example of the SQL you'd write to perform your first example of finding all the descendants of 'A':

WITH RECURSIVE rcte AS (
   SELECT id, letters
   FROM cell 
   WHERE letters = 'A'
   UNION ALL
   SELECT c.id, c.letters
   FROM cell c
   INNER JOIN rcte r
   ON c.parent_cell_id = r.id
)
SELECT letters
FROM rcte
ORDER BY letters;

Explanation

The above SQL sets up a "Common Table Expression", i.e. a SELECT to run whenever its alias (in this case rcte) is referenced. The recursion happens because this is referenced within itself. The first part of the UNION picks the cell at the top of the hierarchy. Its descendants are all found by carrying on joining on children in the second part of the UNION until no further records are found.

Demo

The above query can be seen in action on the sample data here: http://rextester.com/HVY63888