I know there is an easy way to do this...but, I can\'t figure it out.
I have a dataframe in my R script that looks something like this:
A B C
1.2
Here is a solution using the plyr
package
plyr::ddply(df, .(A), summarize, num = length(A), totalB = sum(B))
In dplyr
:
library(tidyverse)
A <- c(1.2, 2.3, 2.3, 1.2, 3.4, 1.2)
B <- c(4, 4, 6, 3, 2, 5)
C <- c(8, 9, 0, 3, 1, 1)
df <- data_frame(A, B, C)
df %>%
group_by(A) %>%
summarise(num = n(),
totalB = sum(B))
I'd use aggregate
to get the two aggregates and then merge
them into a single data frame:
> df
A B C
1 1.2 4 8
2 2.3 4 9
3 2.3 6 0
4 1.2 3 3
5 3.4 2 1
6 1.2 5 1
> num <- aggregate(B~A,df,length)
> names(num)[2] <- 'num'
> totalB <- aggregate(B~A,df,sum)
> names(totalB)[2] <- 'totalB'
> merge(num,totalB)
A num totalB
1 1.2 3 12
2 2.3 2 10
3 3.4 1 2
Here is a solution using data.table
for memory and time efficiency
library(data.table)
DT <- as.data.table(df)
DT[, list(totalB = sum(B), num = .N), by = A]
To subset only rows where C==1
(as per the comment to @aix answer)
DT[C==1, list(totalB = sum(B), num = .N), by = A]