shutil.copytree without files

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刺人心
刺人心 2021-02-13 19:39

I\'m trying use shutil.copytree:

shutil.copytree(SOURCE_DIR, TARGET_DIR, ignore=None)

This copy also files in folder. I need copy only folders

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5条回答
  • 2021-02-13 19:58

    You can do that by providing a "ignore" function

    def ig_f(dir, files):
        return [f for f in files if os.path.isfile(os.path.join(dir, f))]
    
    shutil.copytree(SRC, DES, ignore=ig_f)
    

    Basically, when you call copytree, it will recursively go to each child folder and provide a list of files in that folder to the ignore function to check if those files are suitable based on a pattern. The ignored files will be returned as a list in the end of the function and then, copytree will only copy items excluding from that list (which in your case, contains all the files in the current folder)

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  • 2021-02-13 20:00

    Here's an implementation of @Oz123's solution which is based on os.walk():

    import os
    
    def create_empty_dirtree(srcdir, dstdir, onerror=None):
        srcdir = os.path.abspath(srcdir)
        srcdir_prefix = len(srcdir) + len(os.path.sep)
        os.makedirs(dstdir)
        for root, dirs, files in os.walk(srcdir, onerror=onerror):
            for dirname in dirs:
                dirpath = os.path.join(dstdir, root[srcdir_prefix:], dirname)
                try:
                    os.mkdir(dirpath)
                except OSError as e:
                    if onerror is not None:
                        onerror(e)
    
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  • 2021-02-13 20:02

    You should consider using os.walk.

    Here is an example for os.walk. This way you could list all the directories and then create them with os.mkdir.

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  • 2021-02-13 20:11

    use distutils.dir_util.create_tree to just copy directory structure (not files)

    note : the argument files is a list of filenames. if you want something that would work as shutils.copytree:

    import os
    import distutils.dir_util
    def copy_tree(source, dest, **kwargs):
        filenames = [os.path.join(path, file_) for path, _, files in os.walk(source) for file_ in files]
        distutils.dir_util.create_tree(dest, filenames, **kwargs)
    
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  • 2021-02-13 20:19

    If you want ignore pattern functionality with os.walk(), then:

    ignorePatterns=[".git"]
    def create_empty_dirtree(src, dest, onerror=None):
        src = os.path.abspath(src)
        src_prefix = len(src) + len(os.path.sep)
        for root, dirs, files in os.walk(src, onerror=onerror):
            for pattern in ignorePatterns:
                if pattern in root:
                    break
            else:
                #If the above break didn't work, this part will be executed
                for dirname in dirs:
                    for pattern in ignorePatterns:
                        if pattern in dirname:
                            break
                    else:
                        #If the above break didn't work, this part will be executed
                        dirpath = os.path.join(dest, root[src_prefix:], dirname)
                        try:
                            os.makedirs(dirpath,exist_ok=True)
                        except OSError as e:
                            if onerror is not None:
                                onerror(e)
                    continue #If the above else didn't executed, this will be reached
    
            continue #If the above else didn't executed, this will be reached
    

    This will ignore .git directory.

    Note: This requires Python >=3.2 as I used the exist_ok option with makedirs which isn't available on older versions.

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