I asked this question a while back to delete duplicate records based on a column. The answer worked great:
delete from tbl
where id NOT in
(
select min(id)
fro
Try this one. I created a table tblA with three columns.
CREATE TABLE tblA
(
id int IDENTITY(1, 1),
colA int,
colB int,
colC int
)
And added some duplicate values.
INSERT INTO tblA VALUES (1, 2, 3)
INSERT INTO tblA VALUES (1, 2, 3)
INSERT INTO tblA VALUES (4, 5, 6)
INSERT INTO tblA VALUES (7, 8, 9)
INSERT INTO tblA VALUES (7, 8, 9)
If you replace the select with a delete in the statement below you will have your multiple column delete working.
SELECT MIN(Id) as id
FROM
(
SELECT COUNT(*) as aantal, a.colA, a.colB, a.colC
FROM tblA a
INNER JOIN tblA b ON b.ColA = a.ColA
AND b.ColB = a.ColB
AND b.ColC = a.ColC
GROUP BY a.id, a.colA, a.colB, a.colC
HAVING COUNT(*) > 1
) c
INNER JOIN tblA d ON d.ColA = c.ColA
AND d.ColB = c.ColB
AND d.ColC = c.ColC
GROUP BY d.colA, d.colB, d.colC
This shows the rows you want to keep:
;WITH x AS
(
SELECT col1, col2, col3, rn = ROW_NUMBER() OVER
(PARTITION BY col1, col2, col3 ORDER BY id)
FROM dbo.tbl
)
SELECT col1, col2, col3 FROM x WHERE rn = 1;
This shows the rows you want to delete:
;WITH x AS
(
SELECT col1, col2, col3, rn = ROW_NUMBER() OVER
(PARTITION BY col1, col2, col3 ORDER BY id)
FROM dbo.tbl
)
SELECT col1, col2, col3 FROM x WHERE rn > 1;
And once you're happy that the above two sets are correct, the following will actually delete them:
;WITH x AS
(
SELECT col1, col2, col3, rn = ROW_NUMBER() OVER
(PARTITION BY col1, col2, col3 ORDER BY id)
FROM dbo.tbl
)
DELETE x WHERE rn > 1;
Note that in all three queries, the first 6 lines are identical, and only the subsequent query after the CTE has changed.