Grep Recursive and Count

后端 未结 6 658
夕颜
夕颜 2021-02-13 18:14

Need to search a directories with lots of sub-directories for a string inside files:

I\'m using:

grep -c -r \"string here\" *

How can I

相关标签:
6条回答
  • 2021-02-13 18:53

    I would try a combination of find and grep.

    find . | xargs grep -c "string here"
    

    Anyway, grep -c -r "string here" * works for me (Mac OS X).

    0 讨论(0)
  • 2021-02-13 18:59

    To output only file names with matches, use:

    grep -r -l "your string here" .
    

    It will output one line with the filename for each file which matches the expression searched for.

    0 讨论(0)
  • 2021-02-13 19:00
    grep -rc "my string" ./ | grep :[1-9] >> file_name_by_count.txt
    

    Works like a charm.

    0 讨论(0)
  • 2021-02-13 19:02

    Some solution with AWK:

    grep -r "string here" * | awk 'END { print NR } 1'
    

    Next one is total count, number of files, and number of matches for each, displaying the first match of each one (to display all matches, change the condition to ++f[$1]):

    grep -r "string here" * | 
        awk -F: 'END { print "\nmatches: ", NR, "files: ", length(f); 
                       for (i in f) print i, f[i] } !f[$1]++'
    

    Output for the first solution (searching within a directory for "boost::". I manually cut some too long lines so they fit horizontally):

    list_inserter.hpp:            return range( boost::begin(r), boost::end(r) );
    list_of.hpp:            ::boost::is_array<T>,
    list_of.hpp:            ::boost::decay<const T>,
    list_of.hpp:            ::boost::decay<T> >::type type;
    list_of.hpp:        return ::boost::iterator_range_detail::equal( l, r );
    list_of.hpp:        return ::boost::iterator_range_detail::less_than( l, r );
    list_of.hpp:        return ::boost::iterator_range_detail::less_than( l, r );
    list_of.hpp:        return Os << ::boost::make_iterator_range( r.begin(), r.end() );
    list_of.hpp:            return range( boost::begin(r), boost::end(r) );
    list_of.hpp:            return range( boost::begin(r), boost::end(r) );
    list_of.hpp:            return range( boost::begin(r), boost::end(r) );
    ptr_list_of.hpp:                          BOOST_DEDUCED_TYPENAME boost::ptr_...
    ptr_list_of.hpp:        typedef boost::ptr_vector<T>       impl_type;
    13
    

    Output for the second one

    list_inserter.hpp:            return range( boost::begin(r), boost::end(r) );
    list_of.hpp:            ::boost::is_array<T>,
    ptr_list_of.hpp:                          BOOST_DEDUCED_TYPENAME boost::ptr_...
    
    matches:  13 files:  3
    ptr_list_of.hpp 2
    list_of.hpp 10
    list_inserter.hpp 1
    

    Colors in the result are nice (--color=always for grep), but they break when piped through awk here. So better don't enable them then unless you want to have all your terminal colored afterwards :) Cheers!

    0 讨论(0)
  • 2021-02-13 19:07

    It works for me (it gets the total number of 'string here' found in each file). However, it does not display the total for ALL files searched. Here is how you can get it:

    grep -c -r 'string' file > out && \
        awk -F : '{total += $2} END { print "Total:", total }' out
    

    The list will be in out and the total will be sent to STDOUT.

    Here is the output on the Python2.5.4 directory tree:

    grep -c -r 'import' Python-2.5.4/ > out && \
        awk -F : '{total += $2} END { print "Total:", total }' out
    Total: 11500
    
    $ head out
    Python-2.5.4/Python/import.c:155
    Python-2.5.4/Python/thread.o:0
    Python-2.5.4/Python/pyarena.c:0
    Python-2.5.4/Python/getargs.c:0
    Python-2.5.4/Python/thread_solaris.h:0
    Python-2.5.4/Python/dup2.c:0
    Python-2.5.4/Python/getplatform.c:0
    Python-2.5.4/Python/frozenmain.c:0
    Python-2.5.4/Python/pyfpe.c:0
    Python-2.5.4/Python/getmtime.c:0
    

    If you just want to get lines with occurrences of 'string', change to this:

    grep -c -r 'import' Python-2.5.4/ | \
        awk -F : '{total += $2; print $1, $2} END { print "Total:", total }'
    

    That will output:

    [... snipped]
    Python-2.5.4/Lib/dis.py 4
    Python-2.5.4/Lib/mhlib.py 10
    Python-2.5.4/Lib/decimal.py 8
    Python-2.5.4/Lib/new.py 6
    Python-2.5.4/Lib/stringold.py 3
    Total: 11500
    

    You can change how the files ($1) and the count per file ($2) is printed.

    0 讨论(0)
  • 2021-02-13 19:12

    Using Bash's process substitution, this gives what I believe is the output you want? (Please clarify the question if it's not.)

    grep -r "string here" * | tee >(wc -l)
    

    This runs grep -r normally, with output going both to stdout and to a wc -l process.

    0 讨论(0)
提交回复
热议问题