I want to create this tuple:
a=(1,1,1),(2,2,2),(3,3,3),(4,4,4),(5,5,5),(6,6,6),(7,7,7),(8,8,8),(9,9,9)
I tried with this
a=1,1,
itertools.repeat can also be used here:
>>> from itertools import repeat
>>> [tuple(repeat(i, 3)) for i in range(1, 10)]
[(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6), (7, 7, 7), (8, 8, 8), (9, 9, 9)]
If you want the final result to be in a tuple of tuples instead of a list of tuples, you can wrap tuple
again:
>>> tuple(tuple(repeat(i, 3)) for i in range(1, 10))
((1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6), (7, 7, 7), (8, 8, 8), (9, 9, 9))
A tuple is an immutable list. This means that, once you create a tuple, it cannot be modified. Read more about tuples and other sequential data types here.
So, if you really need to change a tuple during run time:
or
So, in your case:
a = []
for i in range (1,10):
a.append((i,i,i))
a = tuple(a)
print a
If I were to imitate something like this, I would have done it in the following way:
a = tuple((n,n,n) for n in range(1,10))
print(a)
#((1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6), (7, 7, 7), (8, 8, 8), (9, 9, 9))
This is the most simple and pythonic way to do this specific job.
A little experimentation got this working. I guess you need a comma after the tuple in a to convince python it is a tuple.
a = ((1,1,1),)
for i in range(2, 10):
a = a + ((i,i,i),)
print(a)
Use an extra comma in your tuples, and just join:
a = ((1,1,1),)
for i in range(2,10):
a = a + ((i,i,i),)
Edit: Adapting juanpa.arrivillaga's comment, if you want to stick with a loop, this is the right solution:
a = [(1,1,1)]
for i in range (2,10):
a.append((i,i,i))
a = tuple(a)
You can declare it without having to use a loop.
a = tuple((i,)*3 for i in range(1, 10))