How should I create my GUID?

前端 未结 3 1062
[愿得一人]
[愿得一人] 2021-02-13 16:57

I\'m going to be uploading images to a system and need them to be referenced by a non-sequential unique ID. I\'ve read a little about GUIDs, and I\'m wondering what the best app

相关标签:
3条回答
  • 2021-02-13 17:15

    GUID is Microsoft's version of UUID. PHP's uniqid is version 4 of UUID. Definitely good enough.

    0 讨论(0)
  • 2021-02-13 17:16

    EDIT:

    Yikes! I forgot about this ancient answer of mine. To clarify confusion created by my naivety (consistent with the comments made below): MD5 (like most useful hashes, by their nature) are not injective, so their output is not guaranteed to be unique for all inputs.

    If hash collisions are an issue (in this case, they are), using this technique will require checking, after hashing, whether an identical key has already been generated.


    Since uniqid uses the current time in microseconds to generate the guid, there is virtually no chance you'll ever run into the same one twice.

    So if you're just using it to make unique filenames, uniqid() will be sufficient. If you want to prevent users from guessing the guid, you might as well make it harder and md5 it as well.

    0 讨论(0)
  • 2021-02-13 17:24

    I also want to create guid for calling .net api and this function generate a key in guid format and it works for me

    function generateGuid($include_braces = false) {
        if (function_exists('com_create_guid')) {
            if ($include_braces === true) {
                return com_create_guid();
            } else {
                return substr(com_create_guid(), 1, 36);
            }
        } else {
            mt_srand((double) microtime() * 10000);
            $charid = strtoupper(md5(uniqid(rand(), true)));
    
            $guid = substr($charid,  0, 8) . '-' .
                    substr($charid,  8, 4) . '-' .
                    substr($charid, 12, 4) . '-' .
                    substr($charid, 16, 4) . '-' .
                    substr($charid, 20, 12);
    
            if ($include_braces) {
                $guid = '{' . $guid . '}';
            }
    
            return $guid;
        }
    }
    
    0 讨论(0)
提交回复
热议问题