How do I convert an arbitrary double to an integer while avoiding undefined behavior?

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你的背包 2021-02-13 16:27

Let\'s say I\'ve got a function that accepts a 64-bit integer, and I want to call it with a double with arbitrary numeric value (i.e. it may be very large in magnit

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  • 2021-02-13 16:53

    How about:

    constexpr uint64_t weird_high_limit = (double)kint64max == (double)(kint64max-1);
    int64_t clamped = (d >= weird_high_limit + kint64max)? kint64max: (d <= kint64min)? kint64min: int64_t(d);
    

    I think this takes care of all the edge cases. If d < (double)kint64max, then (exact)d <= (exact)kint64max. Proof proceeds by contradiction of the fact that (double)kint64max is the next higher or lower representable value.

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  • 2021-02-13 16:59

    Here's a solution that doesn't fit all the criteria, along with analysis for why not. See the accepted answer for a better answer.

    // Define constants from the question.
    static constexpr int64_t kint64min = std::numeric_limits<int64_t>::min();
    static constexpr int64_t kint64max = std::numeric_limits<int64_t>::max();
    
    int64_t SafeCast(double d) {
      // Handle NaN specially.
      if (std::isnan(d)) return 0;
    
      // Handle out of range below.
      if (d <= kint64min) return kint64min;
    
      // Handle out of range above.
      if (d >= kint64max) return kint64max;
    
      // At this point we know that d is in range.
      return d;
    }
    

    I believe this avoids undefined behavior. There is nothing to be wary of with casting integers to doubles in the range checks. Assuming sanity in the way that non-representable integers are converted (in particular that the mapping is monotonic), by the time the range checks are past, we can be sure that d is in [-2^63, 2^63), as required for the implicit cast at the end of the function.

    I'm also confident that this clamps out of range values correctly.

    The issue is criteria #2 from the update to my question. Consider an implementation where kint64max is not representable as a double, but kint64max - 1 is. Further, assume that this is an implementation where casting kint64max to a double yields the next lower representable value, i.e. kint64max - 1. Let d be 2^63 - 2 (i.e. kint64max - 1). Then SafeCast(d) is kint64max, because the range check converts kint64max to a double, yielding a value equal to d. But static_cast<int64_t>(d) is kint64max - 1.

    Try as I might, I can't find a way to resolve this. Nor can I even write a unit test that checks my criteria, without the unit test executing undefined behavior. I feel like there is a deeper lesson to be learned here—something about the impossibility of detecting whether an action in a system will cause undefined behavior from inside the system itself, without causing undefined behavior.

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  • 2021-02-13 17:03

    It turns out this is simpler to do than I thought. Thanks to Michael O'Reilly for the basic idea of this solution.

    The heart of the matter is figuring out whether the truncated double will be representable as an int64_t. You can do this easily using std::frexp:

    #include <cmath>
    #include <limits>
    
    static constexpr int64_t kint64min = std::numeric_limits<int64_t>::min();
    static constexpr int64_t kint64max = std::numeric_limits<int64_t>::max();
    
    int64_t SafeCast(double d) {
      // We must special-case NaN, for which the logic below doesn't work.
      if (std::isnan(d)) {
        return 0;
      }
    
      // Find that exponent exp such that
      //     d == x * 2^exp
      // for some x with abs(x) in [0.5, 1.0). Note that this implies that the
      // magnitude of d is strictly less than 2^exp.
      //
      // If d is infinite, the call to std::frexp is legal but the contents of exp
      // are unspecified.
      int exp;
      std::frexp(d, &exp);
    
      // If the magnitude of d is strictly less than 2^63, the truncated version
      // of d is guaranteed to be representable. The only representable integer
      // for which this is not the case is kint64min, but it is covered by the
      // logic below.
      if (std::isfinite(d) && exp <= 63) {
        return d;
      }
    
      // Handle infinities and finite numbers with magnitude >= 2^63.
      return std::signbit(d) ? kint64min : kint64max;
    }
    
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  • 2021-02-13 17:09

    boost::numeric_cast, that's how.

    http://www.boost.org/doc/libs/1_56_0/libs/numeric/conversion/doc/html/boost_numericconversion/improved_numeric_cast__.html

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