chop unused decimals with javascript

Question

I\'ve got a currency input and need to return only significant digits. The input always has two decimal places, so:

4.00  ->  4
4.10  ->  4.1
4.01  ->           


        

Answer 1

String(4) // "4"
String(4.1) // "4.1"
String(4.10) // "4.1"
String(4.01) // "4.01"

parseFloat works, but you've got to cast it back to a string.

Answer 2

string to string: parseFloat(value).toFixed(2);
string to number: +(parseFloat(value).toFixed(2))
number to number: Math.round(value*100)/100;
number to string: (Math.round(value*100)/100).toFixed(2);

Answer 3

So you're starting with a string and you want a string result, is that right?

val = "" + parseFloat(val);

That should work. The more terse

val = "" + +val;

or

val = +val + "";

would work as well, but that form is too hard to understand.

How do these work? They convert the string to a number then back to a string. You may not want to use these, but knowing how the JavaScript conversions work will help you debug whatever you do come up with.

Answer 4

I think this is what you want

    v = 33.404034
    v.toFixed(2) # v -> 33.40
    parseFloat(v.toFixed(2)) # 33.4

and you have

    v = 33.00704034
    v.toFixed(2) # v -> 33.01
    parseFloat(v.toFixed(2)) # 33.01

    v = 33.00304034
    v.toFixed(2) # v -> 33.00
    parseFloat(v.toFixed(2)) # 33

Answer 5

I am trying to find a solution like that right now. This is how I got here.

I used Number() function for my application, but looks like it's working the same as parseFloat()

http://jsfiddle.net/4WN5y/

I remove and commas before checking the number.

 var valueAsNumber = Number( val.replace(/\,/g,'') );

Answer 6

Your code also chops off zeros in numbers like "1000". A better variant would be to only chop of zeros that are after a decimal point. The basic replacement with regular expressions would look like this:

str.replace(/(\.[0-9]*?)0+$/, "$1"); // remove trailing zeros
str.replace(/\.$/, "");              // remove trailing dot