Friend function is unable to construct a unique pointer of the class

Question

I have a certain design strategy where the constructor of my class is private and can only be constructed by friends of the class. Inside the friend function, I am trying to cre

Answer 1

Here is another approach I've seen used, apparently known as the passkey idiom : have the public constructor require a private access token.

class Spam {
    struct Token {};
    friend void Foo();
public:
    Spam(Token, int mem) : mem(mem) {}

private:
    int mem;
};

void Foo() {
    std::unique_ptr<Spam> spam = std::make_unique<Spam>(Spam::Token{}, 10);
}

void Bar() {
    // error: 'Spam::Token Spam::token' is private
    // std::unique_ptr<Spam> spam = std::make_unique<Spam>(Spam::Token{}, 10);
}

Answer 2

Why am I not able to compile?

You are unable to compile because make_unique is not a friend of Spam.

An alternative solution to making make_unique a friend is to move the creation of the unique_ptr into Spam.

class Spam {
   ...
private:
   Spam(int) {}

   static unique_ptr<Spam> create( int i ) 
   { return std::unique_ptr<Spam>( new Spam(i) ); }
};

and then have Foo call that instead.

void Foo() {
    std::unique_ptr<Spam> spam = Spam::create(10);
    ...
}

Answer 3

In your case the function make_unique is trying to create an instance of Spam and that function is not a friend. Calling a non-friend function from inside a friend function does not imbue the non-friend function with friend status.

To solve this you can write in Foo:

std::unique_ptr<Spam> spam(new Spam(10));

Answer 4

In your example, Foo() is a friend, but it isn't the function that's creating the Spam - make_unique is internally calling new Spam itself. The simple fix is to just have Foo() actually construct the Spam directly:

void Foo() {
    std::unique_ptr<Spam> spam(new Spam(10));
}