I have a string \'2009-06-24 09:52:43.000\', which I need to insert to a DateTime column of a table.
But I don\'t care about the time, just want to insert it as 2009-06-
SELECT CAST(CONVERT(VARCHAR,GETDATE(),102) AS DATETIME)
SELECT CAST(CONVERT(VARCHAR(10),'2009-06-24 09:52:43.000',102) AS DATETIME)
Strip the time, and cast it to date:
select cast(left(yourstring, 10) as datetime)
declare @originalDate datetime
select @originalDate = '2009-06-24 09:52:43.000'
declare @withoutTime datetime
select @withoutTime = dateadd(d, datediff(d, 0, @originalDate), 0)
select @withoutTime
If you will always have the date in the same format, i.e. yyyy-MM-DD you can grab the first 10 characters if the value and insert that which is the equivelant of 00:00:00.0000 time for that date.
select left('2009-12-32 4:32:00',10)
This is a very efficient way to do this as it does't require converting data types HOWEVER, it does require that the date will always be formatted with a four digit year and two digit day & month.
I have found that casting as a date, then to a datetime to be very efficient and intuitive.
SELECT CAST(CAST(GETDATE() as date) as datetime)
cast it to a date, and then you can use CONVERT to get just the date.
INSERT MyTable(Column1)
SELECT CONVERT(CHAR(8), CAST('2009-06-24 09:52:43.000' AS DATETIME), 112)