JSONObject - How to get a value?

Question

I\'m using a java class on http://json.org/javadoc/org/json/JSONObject.html.

The following is my code snippet:

String jsonResult = UtilMethods.getJSON(         


        

Answer 1

This may be helpful while searching keys present in nested objects and nested arrays. And this is a generic solution to all cases.

import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

public class MyClass
{
    public static Object finalresult = null;
    public static void main(String args[]) throws JSONException
    {
        System.out.println(myfunction(myjsonstring,key));
    }

    public static Object myfunction(JSONObject x,String y) throws JSONException
    {
        JSONArray keys =  x.names();
        for(int i=0;i<keys.length();i++)
        {
            if(finalresult!=null)
            {
                return finalresult;                     //To kill the recursion
            }

            String current_key = keys.get(i).toString();

            if(current_key.equals(y))
            {
                finalresult=x.get(current_key);
                return finalresult;
            }

            if(x.get(current_key).getClass().getName().equals("org.json.JSONObject"))
            {
                myfunction((JSONObject) x.get(current_key),y);
            }
            else if(x.get(current_key).getClass().getName().equals("org.json.JSONArray"))
            {
                for(int j=0;j<((JSONArray) x.get(current_key)).length();j++)
                {
                    if(((JSONArray) x.get(current_key)).get(j).getClass().getName().equals("org.json.JSONObject"))
                    {
                        myfunction((JSONObject)((JSONArray) x.get(current_key)).get(j),y);
                    }
                }
            }
        }
        return null;
    }
}

Possibilities:

1. "key":"value"
2. "key":{Object}
3. "key":[Array]

Logic :

• I check whether the current key and search key are the same, if so I return the value of that key.
• If it is an object, I send the value recursively to the same function.
• If it is an array, I check whether it contains an object, if so I recursively pass the value to the same function.

Answer 2

String loudScreaming = json.getJSONObject("LabelData").getString("slogan");

Answer 3

If it's a deeper key/value you're after and you're not dealing with arrays of keys/values at each level, you could recursively search the tree:

public static String recurseKeys(JSONObject jObj, String findKey) throws JSONException {
    String finalValue = "";
    if (jObj == null) {
        return "";
    }

    Iterator<String> keyItr = jObj.keys();
    Map<String, String> map = new HashMap<>();

    while(keyItr.hasNext()) {
        String key = keyItr.next();
        map.put(key, jObj.getString(key));
    }

    for (Map.Entry<String, String> e : (map).entrySet()) {
        String key = e.getKey();
        if (key.equalsIgnoreCase(findKey)) {
            return jObj.getString(key);
        }

        // read value
        Object value = jObj.get(key);

        if (value instanceof JSONObject) {
            finalValue = recurseKeys((JSONObject)value, findKey);
        }
    }

    // key is not found
    return finalValue;
}

Usage:

JSONObject jObj = new JSONObject(jsonString);
String extract = recurseKeys(jObj, "extract");

Using Map code from https://stackoverflow.com/a/4149555/2301224

Answer 4

You can try the below function to get value from JSON string,

public static String GetJSONValue(String JSONString, String Field)
{
       return JSONString.substring(JSONString.indexOf(Field), JSONString.indexOf("\n", JSONString.indexOf(Field))).replace(Field+"\": \"", "").replace("\"", "").replace(",","");   
}