How to verify PAN card?

Question

How to check the validation of edittext for pan card like \"ABCDE1234F\". I am confused how to check the the validation for this. Please help me guys. I will appreciate any kind

Answer 1

This is perfect PAN number RegEx: :

String panNumber = "AAAPL1234C"; // get your editext value here
Pattern pattern = Pattern.compile("[A-Z]{3}[ABCFGHLJPTF]{1}[A-Z]{1}[0-9]{4}[A-Z]{1}");

Matcher matcher = pattern.matcher(panNumber );
// Check if pattern matches 
if (matcher.matches()) {
    Log.i("Matching","Yes");
}

There are some condition for PAN number as follow :

The PAN (or PAN number) is a ten-character long alpha-numeric unique identifier.

The PAN structure is as follows: AAAPL1234C:

The first five characters are letters (in uppercase by default), followed by four numerals, and the last (tenth) character is a letter. The first three characters of the code are three letters forming a sequence of alphabets letters from AAA to ZZZ

The fourth character identifies the type of holder of the card. Each holder type is uniquely defined by a letter from the list below:

• A — Association of persons (AOP)
• B — Body of individuals (BOI)
• C — Company
• F — Firm
• G — Government
• H — HUF (Hindu undivided family)
• L — Local authority
• J — Artificial juridical person
• P — Individual (proprietor)
• T — Trust (AOP)
• F – LLP (limited liability partnership)

The fifth character of the PAN is the first character of either:

• of the surname or last name of the person, in the case of a "personal" PAN card, where the fourth character is "P" or
• of the name of the entity, trust, society, or organisation in the case of a company/HUF/firm/AOP/trust/BOI/local authority/artificial judicial person/government, where the fourth character is "C", "H", "F", "A", "T", "B", "L", "J", "G". The last (tenth) character is an alphabetic digit used as a check-sum to verify the

Answer 2

pan card validation

regex : /(^([a-zA-Z]{5})([0-9]{4})([a-zA-Z]{1})$)/

Answer 3

Note that none of other answers available so far doesn't verify PAN check digit.

Here is Luhn algorythm from http://rosettacode.org/wiki/Luhn_test_of_credit_card_numbers#Java:

public static boolean luhnTest(String number) {
    int s1 = 0, s2 = 0;
    String reverse = new StringBuffer(number).reverse().toString();
    for (int i = 0 ; i < reverse.length(); i++){
        int digit = Character.digit(reverse.charAt(i), 10);
        if (i % 2 == 0) { //this is for odd digits, they are 1-indexed in the algorithm
            s1 += digit;
        } else { //add 2 * digit for 0-4, add 2 * digit - 9 for 5-9
            s2 += 2 * digit;
            if (digit >= 5) {
                s2 -= 9;
            }
        }
    }
    return (s1 + s2) % 10 == 0;
}

Answer 4

Hi for pan card verification you need to execute two step process in your project.

1.) create a form and get user pan card number

2.) upload user pan card image

After complete both step make a logic in backend for verification. For this you can follow below tutorial:

https://www.lelocode.com/posts/pan-verification-in-laravel-using-baidu-ocr-universal-text-recognition-%28high-precision-version%29

Answer 5

^([a-zA-Z]){5}([0-9]){4}([a-zA-Z]){1}?$/

Try This, hope will work

Answer 6

You can use Key press Event for PAN Card Validation in C#

enter code here

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)

    {           
        int sLength = textBox1.SelectionStart;  

        switch (sLength)
        {
            case 0:

            case 1:

            case 2:

            case 3:

            case 4:

                    if (char.IsLetter(e.KeyChar) || Char.IsControl(e.KeyChar))
                    {
                        e.Handled = false;
                    }
                    else
                    {
                        e.Handled = true;
                    }
                    break;

            case 5:

            case 6:

            case 7:

            case 8:
                    if (char.IsNumber(e.KeyChar) || Char.IsControl(e.KeyChar))
                    {
                        e.Handled = false;
                    }
                    else
                    {
                        e.Handled = true;
                    }
                    break;
            case 9:
                    if (char.IsLetter(e.KeyChar) || Char.IsControl(e.KeyChar))
                    {
                        e.Handled = false;
                    }
                    else
                    {
                        if (Char.IsControl(e.KeyChar))
                        {
                            e.Handled = false;
                        }

                        else
                        {
                            e.Handled = true;
                        }
                    }
                    break;
            default:
                    if (Char.IsControl(e.KeyChar))
                    {
                        e.Handled = false;
                    }

                    else
                    {
                        e.Handled = true;
                    }
                    break;
        }
    }