jquery selector - exclude first and second

Question

I want to exclude first and second element from jquery selector. I tried this:

$(\'p:not(:nth-child(1),:nth-child(2))\')

But this only excludes

Answer 1

try:

$('p:not(:nth-child(1)),p:not(:nth-child(2))')

Reference: http://www.w3.org/TR/selectors/#negation

from that reference: "The negation pseudo-class, :not(X), is a functional notation taking a simple selector (excluding the negation pseudo-class itself) as an argument...."

Answer 2

Simply:

$('p:gt(1)')

http://api.jquery.com/gt-selector/

Demo http://jsfiddle.net/NtFYq/1/

As Alnitak has pointed out in the comment, if performance is a concern, you can use his solution of slice

Thanks a lot @Alnitak for pointing that out :)

Answer 3

 $('p').not(":nth-child(1)").not(":nth-child(2)")

-- SEE DEMO --

Answer 4

$('p').not($('p').eq(0), $('p').eq(1)) 

Answer 5

This jQuery sequence uses .slice() to discard the first two elements from the $('p') selector:

$('p').slice(2).

see http://jsfiddle.net/alnitak/zWV7Z/

Note that this is not the same as nth-child - the exclusion is based on the whole set of elements found in the first selector, and not on their relative position in the DOM.