Java String.split() Regex

Question

I have a string:

String str = \"a + b - c * d / e < f > g >= h <= i == j\";

I want to split the string on all of the operators

Answer 1

You could split on a word boundary with \b

Answer 2

String[] ops = str.split("\\s*[a-zA-Z]+\\s*");
String[] notops = str.split("\\s*[^a-zA-Z]+\\s*");
String[] res = new String[ops.length+notops.length-1];
for(int i=0; i<res.length; i++) res[i] = i%2==0 ? notops[i/2] : ops[i/2+1];

This should do it. Everything nicely stored in res.

Answer 3

str.split (" ") 
res27: Array[java.lang.String] = Array(a, +, b, -, c, *, d, /, e, <, f, >, g, >=, h, <=, i, ==, j)

Answer 4

    String str = "a + b - c * d / e < f > g >= h <= i == j";
    String reg = "\\s*[a-zA-Z]+";

    String[] res = str.split(reg);
    for (String out : res) {
        if (!"".equals(out)) {
            System.out.print(out);
        }
    }

Output : + - * / < > >= <= ==

Answer 5

Can you invert your regex so split by the non operation characters?

String ops[] = string.split("[a-z]")
// ops == [+, -, *, /, <, >, >=, <=, == ]   

This obviously doesn't return the variables in the array. Maybe you can interleave two splits (one by the operators, one by the variables)

Answer 6

You could also do something like:

String str = "a + b - c * d / e < f > g >= h <= i == j";
String[] arr = str.split("(?<=\\G(\\w+(?!\\w+)|==|<=|>=|\\+|/|\\*|-|(<|>)(?!=)))\\s*");

It handles white spaces and words of variable length and produces the array:

[a, +, b, -, c, *, d, /, e, <, f, >, g, >=, h, <=, i, ==, j]