use slugify in template

Question

I want to have SEO-friendly URL,my current url in urls.py :

(ur\'^company/news/(?P.*)/(?P\\d+)/$\',\'C         


        

Answer 1

Have you tried n.title|slugify and see if that works for you.

ref: https://docs.djangoproject.com/en/dev/ref/templates/builtins/?from=olddocs#slugify

Note: although this is possible, just make sure the 'slugified' element is never used for any part of routing... (ie, purely for display only)

Answer 2

This will generate the needed url:

{% for n in news %}
      <a href="{% url CompanyHub.views.getNews n.title|slugify n.pk %}" >{{n.description}}</a>
{% endfor %}

The examples above save slugify_field in database, as they later search for it. Otherwise in database you'll have a normal title, and slugified title in code for searching.. No easy way to compare them. But the way you've explained is simpler. You will have this kind of view:

def news(request, slug, news_id):
    news = News.objects.filter(pk=news_id)

UPDATE: To use unicode symbols in slugify, you'll need a conversion first. Look at this: How to make Django slugify work properly with Unicode strings?. It uses the Unidecode library

Then add a custom filter:

from unidecode import unidecode
from django.template.defaultfilters import slugify

def slug(value):
    return slugify(unidecode(value))

register.filter('slug', slug)

then in your template use this:

{% load mytags %}
<a href="{% url CompanyHub.views.getNews n.title|slug n.pk %}

Here is an example:

{{ "影師嗎 1 2 3"|slug}}

renders as:

ying-shi-ma-1-2-3